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True [87]
3 years ago
14

Do the phrases 6 less a number y and 6 less than a number y mean the same thing? Explain. A. No, they do not both mean the same

thing. 6 less a number y can be represented by the expression 6 - y. 6 less than a number y can be represented by the expression y - 6. B. Yes, they both mean the same thing. They can also both be represented by the expression y - 6.
Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

B. Yes, they both mean the same thing. They can also both be represented by the expression y - 6.

Step-by-step explanation:

Given

Phrase 1: 6 less a number y

Phrase 2: 6 less than a number y

<em>Mathematically,</em>

Phrase 1 can be represented as follows;

y - 6

<em>Mathematically,</em>

Phrase 2 can be represented as follows;

y - 6

<em>Since the representation  of both phrases are the same, then option B answers the question.</em>

<em></em>

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Look at this set of 8 numbers:33769234 how would the range change if the number 6 replaced the number 7 in the set
klio [65]
Put the numbers in order

2,3,3,3,4,6,7,9.....the range is the largest number minus the smallest number
so as it is, the range is (9 - 2) = 7

if u replaced the 7 with a 6...
2,3,3,3,4,6,6,9...the range is STILL (9 - 2) = 7
3 0
3 years ago
Help!!! ASAP<br> A PASS OR FAIL!! Help
marysya [2.9K]

Answer:

48/73

Step-by-step explanation:

cos S in ratio = ?

cos S = Adjacent/hypothenus

adjacent is the dimension of line aside the opposite (the line facing angle S, the hypotenus(longest line)

adjacent = 48

hypothenus = 73

cos S= 48/73

5 0
3 years ago
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43 is a number between
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5 0
3 years ago
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\&#10;x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
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