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fiasKO [112]
3 years ago
6

//////////help me\\\\\\\\\\\\\​

Mathematics
2 answers:
Nookie1986 [14]3 years ago
6 0

Answer:

c the answer is c just trust me

andreev551 [17]3 years ago
5 0
I can’t see the photo is blurry
You might be interested in
If the sum of two whole numbers is 24 more than their difference, then one of the number must be
yuradex [85]

Answer:

Answer would be c

Step-by-step explanation:

12+12=24   12-12=0

8 0
4 years ago
Read 2 more answers
A bag contains three red marbles, three green ones, one lavender one, one How many sets of five marbles include at least two red
dimaraw [331]

Answer with Step-by-step explanation:

The number of marbles are as under

3 red , 3 green , 1 Lavender total = 7

Now to select five marbles from a total of 7 marbles such that at least 2 marbles are included are the sum of the following cases:

1) We select 2 exactly 2 red marbles from 3 reds and the remaining 3 marbles are selected from 4 of other colours

Thus n_{1}=\binom{3}{2}\binom{4}{3}=\frac{3!}{2!}\cdot \frac{4!}{3!}=12

2)We select all the 3 red marbles and the remaining 2 are selected from the remaining 4 marbles

n_2=\binom{4}{2}=\frac{4!}{2!\cdot 2!}=6

Thus the total number of ways are n_1+n_2=12+6=18

3 0
3 years ago
translate this into an expression: the quotient of a number, x, and 8, could you please explain it to me?​
Xelga [282]

Answer:

x/8

Step-by-step explanation:

First, we are given "the quotient of...". This means that we are dividing something/something else. If two numbers are given in the phrase "something and something else", the first number given will be the something, and the second number will be the something else.

The first number listed is x. Therefore, we have

x/something else.

Next, we are given "and 8", so we have x/8 as our expression

3 0
3 years ago
PLEase help me out (PLSSSSSS)PLSSSSSS
goldenfox [79]

Answer:

1. Y

2.N (Positive 8)

3. N (< 5)

4. Y

5.N

7 0
4 years ago
Please Help!!!
Leni [432]
<h2>Answer : (2.67, 3.53)</h2><h2></h2>

Step to step explanation:

Confidence interval for mean, when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n= sample size

s= sample standard deviation

t_{\alpha/2} = Critical t-value for n-1 degrees of freedom

We assume the family size is normal distributed.

Given, n= 31 , \overline{x}=3.1, s= 1.42 ,

\alpha=1-0.9=0.10

Critical t value for \alpha/2=0.05 and degree of 30 freedom

t_{\alpha/2} = 1.697  [By t-table]

The required confidence interval:

3.1\pm ( 1.697)\dfrac{1.42}{\sqrt{31}}\\\\=3.1\pm0.4328\\\\=(3.1-0.4328,\ 3.1+0.4328)=(2.6672,\ 3.5328)\approx(2.67,\ 3.53)

Hence,  the 90% confidence interval for the estimate = (2.67, 3.53)

6 0
3 years ago
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