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3 years ago

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An 8 pack of Gatorade costs $4.98, what is the unit rate for each Gatorade bottle rounded to the nearest cent

1 answer:

hammer [34]3 years ago

6 0

Answer:

<h3>5.00 $</h3>

Step-by-step explanation:

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Jeff bought a bottle of water for $2. He also bought some hot dogs for $3 each. Jeff did not spend more than $14 on the hot dogs

lions [1.4K]

Answer:

3H - 2 ≤ 14 I believe.

If i'm wrong forgive me

6 0

2 years ago

Read 2 more answers

A total of 8,644 people went to the football game. Of thos the visitors side. Of the people sitting on the visitor's side filled

lisov135 [29]

You divide 8644 by 8 which equals 1080.5, but since you can't have half of one person you approximate it to 1080 or 1081.

3 0

3 years ago

Below are two parallel lines with a third line intersecting them.

Scrat [10]

Answer:

x = 53 degree

Step-by-step explanation:

53 degree angle = x angle( alternate exterior angle)

Therfore, x = 53 degree

Mark as brainliest

3 0

2 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

Given cos(angle) = -5/13 where the terminal arm of angle lies in quadrant 2, evaluate each trigonometric expression

Mrrafil [7]

Answer the answer is 76.6

Step-by-step explanation:

3 0

2 years ago