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AnnZ [28]
3 years ago
5

I’m really confused please help

Mathematics
1 answer:
sveticcg [70]3 years ago
6 0

Answer: probly d

Step-by-step explanation:

a ,b ,and c are subtracting makeing it hard top get something that was not in the problem

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If f(x) = 2x + 3 and g(x) =4x - 1, find f(4).
fomenos

Solve the "f" function with substitute 4 and solve the "g" function with what we get for the "f" function.

f(4) = 2(8) + 3

f(4) = 16 + 3

f(4) = 19

g(19) = 4(19) - 1

g(19) = 76 - 1

g(19) = 75

Best of Luck!

6 0
3 years ago
Macy is painting a design that contains two repeating patterns. One pattern repeats every 8 inches. The other repeats every 12 i
spayn [35]

Answer:

8-inch pattern is fully printed 28 times.

12-inch pattern is fully printed 19 times.

Patterns start at the same place 9 times

Step-by-step explanation:

1. 19 feet is 228 inches.

2. 8-inch pattern is fully printed 28 times.

3. 12-inch pattern is fully printed 19 times.

4. 8-inch patterns starts at`0,8,16,24,32,40,48...

5. 12-inch pattern starts at 0,12,24,48...

6. As you see they start at the same place after 24 inches.

7. 228/24=9.5, => They start at the same place 9 times.

3 0
3 years ago
(Pythagorean theorem)
shusha [124]

Answer:

S ≈ 16.49 cm and R ≈ 16.76 cm

Step-by-step explanation:

We are given that:

Length = 16 cm

Width = 4 cm

Height = 3 cm

Thus,

The diagonal S of the bottom side is given by pythagoras theorem;

S² = 16² + 4²

S² = 256 + 16

S² = 272

S = √272

S ≈ 16.49 cm

Since we now have the bottom diagonal, then we can use Pythagoras Theorem to find the diagonal "R" of the box:

So, R² = S² + 3²

R² = (√272)² + 9

R² = 272 + 9

R = √281

R ≈ 16.76 cm

8 0
3 years ago
A pebble falls off of a cliff at a height of
kirill115 [55]

Answer:12

Step-by-step explanation: just did the assignment

7 0
3 years ago
What is the first step in solving the inequality 2x + 3 ≥ 17?Divide the left side by 2.Subtract 3 from both sides.Change the dir
Wewaii [24]

Answer:

Subtract 3 from both sides.

Step-by-step explanation:

4 0
4 years ago
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