A. Reflection over y = 2
B. Reflection over y axis, reflection over y = 1
C. I'm guessing you just have to draw this one, just put the center on (2,0) and enlarge it by the scale factor
Answer:
Step-by-step explanation:
The prices of quoted of auto repairs are as listed below;
$139, $150, $345, $99, $167, $155, $140, $200.
For her to check whether there is an outlier in the data, she needs to find the mean of the set of data. An outlier is a value in a set of a data that varies considerably from other data in a dataset. It may be larger or smaller than other set of datas. An outlier can affect the decision of a set of data to be analysed if nor taken care of.
From the data, the possible outliers are $99 and $345
Mean of the data = sum of all the prices/sample size
xbar = \sum Xi / N
Xi are individual datas
\sum Xi = $139+$150+$345+$99+$167+$155+$140+$200+$160
\sumXi = $1555
Sample size = 9
Mean = $1555/9
Mean = $172.78
Hence the value that would best represent the central tendency is $177.78
The answer is -3.
If we add positive one/+1 to negative four/-4, we subtract +1 from -4, giving us -3.
5/6 x 360 = 300
divide 360 by 6 = 60, then multiply 60 by 5 and you get 300.00
