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2 years ago

What is 934-1?

Mathematics

1 answer:

galben [10]2 years ago

7 0

Answer:

933 :)

Also are you ok? Just checking to make sure you’re good

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Josh Pruitt worked 48.75 hours.

leva [86]

For this case, as Josh worked more than 40 hours, he was able to receive a payment
($ 8.20 / h) * (40 h) = 328
1.5(8.20) *8.75 = <span> <span>107.625
</span></span> 328+107.625= 435.625
the gross earnings for Pruitt are 435.625 $

6 0

3 years ago

A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi

SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

$= \frac{20!}{(20-5)! 5!)}$

$= \frac{20*19*18*17*16}{5*4*3*2*1}$

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

$= \frac{20}{320} = \frac{1}{19}$

P(A5) = ⁸C₅ / ²⁰C₅

$= \frac{56}{15540} = \frac{7}{1938}$

P(A4) = ⁷C₄ / ²⁰C₄

$= \frac{35}{4845} = \frac{7}{969}$

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0

3 years ago

Aaron has a triathlon. Sunday he bikes 12 5/8 miles and swims 5 2/3 miles. Monday, he runs 6 3/8 miles. How many total miles Aar

Alla [95]

Let’s put these into one fraction each:

Biking:
= (12*5)/8 miles
= 60/8 miles
This can be reduced to,
= 15/2 miles

Swimming:
= (5*2)/3 miles
= 10/3 miles

Running:
= (6*3)/8 miles
= 18/8 miles
This can be reduced to,
= 9/4

Now we add all the distances up:
= (15/2) + (10/3) + (9/4)

Now we just can add the numerators and the denominators. We must find the lowest common factor (LCF) for our 3 denominators (2,3,4). Our LCF turns out to be 12. *Remember what we do to the denominator we must do to the numerator. So:
= (15/2) + (10/3) + (9/4)
= [(15*6)/12] + [(10*4)/12] + [(9*3)/12]
= (90/12) + (40/12) + (27/12)
= (157/12)
Therefore Aaron Ran 157/12 miles or 13.08 miles.

Hope this helps!

4 0

3 years ago

Ryan achieved an 89% on the same multiple choice test. He answered some questions correctly, left at least one blank and

yKpoI14uk [10]

Answer:

Ryan could have answered multiple choice answers and true or false answers rather than knowledge answer like written prompts

Step-by-step explanation:

Hope this helped:)

5 0

2 years ago

Gym class of 30 boys and 45 girls is divided into groups each group has the same number of students each group has only boys or

Alexus [3.1K]

The greatest number of groups is 15. This is because 15 is a common multiple of 30 and 45

7 0

3 years ago