<span>You are given a rectangular picture measuring 8 inches by 7 inches. Also, Alistair wants this to be framed and that the total area is 34 square inches. The width of the frame is x inches. To solve the dimension of the frame with value of x we have:
We have to assume that x here will be equal to all sides of the frame and so, using the area of the rectangle, we can model the equation like this:
A = LW (where A is the area, L is the length and W is the width)
36 = (8 - x)(7 - x)
36 = 56 - 8x - 7x + x</span>²
<span>x</span>² - 15x +20 = 0 → model of our equation and in quadratic form
x² - 15x + 20 = 0
using a calculator, x = 1.48 inches
<span>
3.Use the equation you created in part A to find the width of the picture frame</span>
Answer:
20
Step-by-step explanation:
16=1 2/10R + -8
16+8= 12/10R
24=12/10R
R=20
Answer:
im not sure but i think its 0.25
Step-by-step explanation:
Answer:
f(x) = 26500 * (0.925)^x
It will take 7 years
Step-by-step explanation:
A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.
To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.
