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julsineya [31]
3 years ago
13

Someone answer this please!

Mathematics
2 answers:
katrin [286]3 years ago
6 0

Answer:

D

Step-by-step explanation:

The guy above me is correct

enyata [817]3 years ago
4 0

Answer:

D

Step-by-step explanation:

11 can fit into 44

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Show you work for full credit Use the SUBSITUTION method or ELIMINATION method to solve this system of equations. y = 4x and 8x
vodka [1.7K]

Answer:

A. (3/2, 6)

Step-by-step explanation:

Use the substitution method:

8x + y = 18 and y = 4x

8x +4x = 18

12x = 18

x = 18/12 = 3/2

y = 4x

= 4(3/2)

= 12/2

= 6

8 0
2 years ago
since this question was deleted i am going to do it again can i please have a free brainliest plz i dont have almost any it will
Alex73 [517]

Answer:

hellooooo, how can I help you? hshshs

7 0
3 years ago
Please help this is it
valkas [14]

Answer:

2t+5

Step-by-step explanation:

8 0
3 years ago
Can someone help me
Roman55 [17]

Answer: D) Reflection across the y-axis; 270^{\circ} counterclockwise rotation about the origin

3 0
2 years ago
The population of a town with a 20162016 population of 87 comma 00087,000 grows at a rate of 1.91.9​% per year. a. Find the rate
SCORPION-xisa [38]

Answer:

Given,

The initial population, P = 87,000,

Annual rate of increasing, r = 1.9 %,

a) Thus, the population after t years,

A=P(1+\frac{r}{100})^t

A=87000(1+\frac{1.9}{100})^{t}

=87000(1+0.019)^t

=87000(1.019)^t

87000(1.019)^t=87000e^{kt}

Where, k is the rate constant,

By comparing,

\implies k=log(1.019)=0.00817418400643\approx 0.00817

Hence, the approximate value of k is 0.00817.

And, the exponential growth function would be,

A=87000e^{0.00817t}

b) If A = 145,000,

145000=87000(1.019)^t

By using graphing calculator,

We get,

t=27.14\approx 27

The year after 27 years from 2016 is 2043.

Hence, in 2043 the population reach 145,000​.

6 0
4 years ago
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