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elixir [45]
3 years ago
5

HIII PLEASE HELP ITS 6 GRADE MATHS LOLL

Mathematics
1 answer:
klio [65]3 years ago
8 0

Answer:

-5, -7, -4, -6, -10

Step-by-step explanation:

Hope this helps!

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Help please!! It would be nice if you could add an explanation, but you don't have to. I just need the answer.
Firlakuza [10]
The answer is B I solved this my self
4 0
3 years ago
A certain shop repairs both audio and video components. Let A denote the event that the next
alexdok [17]

Answer:

0.12 is the required probability.

Step-by-step explanation:

We are given the following in the question:

A: next  component brought in for repair is an audio component

B: event that the next component  is a compact disc player

B \in A

P(A)= 0.6\\P(B) =0.05

We have to evaluate:

P(B|A) = \dfrac{P(B\cap A)}{P(A)}\\P(B|A) = \dfrac{P(B)}{P(A)}\\\\P(B|A) = \dfrac{0.05}{0.6} = 0.12

0.12 is the required probability.

3 0
4 years ago
Review: Angle Bisectors
zmey [24]

Answer:

  • m∠AOC = 15°
  • m∠BOC = 15°

Step-by-step explanation:

Given the angle ∠AOB

It is stated that CO is the angle bisector of ∠AOB.

Given that ∠AOB = 30°

As we know that the angle bisector bisects the angle into two equal angles.

Thus, the angle bisector CO bisects the angle ∠AOB into two equal angles, which are:

  • m∠AOC
  • m∠BOC

as

∠AOB = 30°

Thus, the two formed angles i.e m∠AOC and m∠BOC by the angle bisector would be half of the angle bisector as the angle bisector bisects the angle ∠AOB into two equal angles.

Therefore,

  • m∠AOC = 15°
  • m∠BOC = 15°
7 0
3 years ago
Please Help ASAP!!
Brilliant_brown [7]

Answer:

The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.

Step-by-step explanation:

In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't.  Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype.  However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.  

4 0
4 years ago
W divided into 7 equals 15
olasank [31]
Multiply both sides by 7. w=<span>105</span>
6 0
3 years ago
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