Answer:
500+10+0
Step-by-step explanation:
Answer:
Ben is 19 Ishaan is 7
Step-by-step explanation:
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Given :
A trailer will be used to transport several 40-pound crates to a store.
The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.
An 82-pound crate has already been loaded onto the trailer.
To Find :
The greatest number of 40-pound crates that can be loaded onto the trailer.
Solution :
Weight left = 1050 - 80 = 970 pound.
Let, number of 40 pounds crates that can be loaded are x.

Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.
Hence, this is the required solution.
1.5x1/5=.3
half of 1.5 (because of 2 lbs of dried fruit ) is .75
.75+.3=.78 cents for 1 lb