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Gala2k [10]
3 years ago
9

Tickets to a musical cost $15 for adults and $6 for students. Mr. James and Mrs. Reagan are taking their classes to the musical.

If 8 adults, including the teachers, went along as chaperones and the total cost for the combined classes to attend the musical was $480, how many students attended the musical?
Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
4 0
That is not the answer, the answer is 60 students... what I did was 8x15 to get 120, then I subtracted 480-120 to get 360. 360 is the amount of money the kids cost. Finally I divided 360 by 6 to get 60 because each student was 6$
faltersainse [42]3 years ago
3 0
The answer to your question is 9
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Find the mean of the data summarized in the given frequency distribution . Compare the computed mean to the actual mean of 57.6
AlexFokin [52]

The mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F is lesser than the actual mean of 57.6° F.

<h3>What is the mean of a distribution?</h3>

The mean of the distribution can be defined as the average value of the distribution, It can be expressed as the total sum of all the observed values divided by the frequency of the distribution.

From the parameters given:

Low-temperature             Frequency

40 - 44                                    2

45 - 49                                    5

50 - 54                                    9

55 - 59                                    6

60 - 64                                    3

The first thing to do is to determine the class midpoint. The class midpoint is the sum of the class interval divided by 2.

The class midpoint of 40 - 44 is \mathbf{\dfrac{40 + 44}{2} = 42}

The class midpoint of 45 - 49 is \mathbf{\dfrac{45 + 49}{2} = 47}

The class midpoint of 50 - 54 is \mathbf{\dfrac{50 + 54}{2} = 52}

The class midpoint of 55 - 59 is \mathbf{\dfrac{55 + 59}{2} = 57}

The class midpoint of 60 - 64 is \mathbf{\dfrac{60 + 64}{2} = 62}

Now, the table can be represented as:

Low-temperature             Frequency          x  

40 - 44                                    2                   42

45 - 49                                    5                   47

50 - 54                                    9                   52

55 - 59                                    6                   57

60 - 64                                    3                   62

The mean can now be determined as follows:

\mathbf{\bar x = \dfrac{\sum fx}{\sum f }}

\mathbf{\bar x = \dfrac{(2 \times 42)+ (5 \times 47) + ( 9\times 52) +(6\times 57) + (3 \times 62)}{2 + 5 + 9 + 6 + 3 }}

\mathbf{\bar x = \dfrac{1315}{25}}

\mathbf{\bar x = 52.6}

Therefore, we can conclude that the mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F. is lesser than the actual mean of 57.6° F

Learn more about the mean of frequency distribution here:

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In order to solve this problem, we transform the statements into algebraic expressions. First, we assign the variables.

 

Let:

x = Gina’s number

y = Sara’s number

 

For the first equation, we show that Gina’s number is greater than Sara’s number by 2. For the second equation, we show that the sum of both numbers is 68.

<span>(1)  </span>x – y = 2

<span>(2)  </span>x + y = 68

 

<span>We add the two expressions, which result in the expression: 2x = 70. Then we divide 70 by 2 to get the value of x. We then have x = 35. Using the second equation, we solve for y = 68-35. This gives y = 33. To summarize, Gina’s number is 35 while Sara’s number is 33.</span>
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