Pleaseeeeeee helppppppp I am being timed
1 answer:
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Answer:
(A)T(–2, 4) ry-axis
Step-by-step explanation:
The graph showing triangles MNO and M"N"O" is attached below.
From the graph, the coordinates are:
- M(5,-4),N(3,-2) and O(1,-3)
- M"(-3,0), N"(-1,2) and O"(1,1)
When we <u>transform triangle MNO by (-2,4),</u> we obtain:
M'(3,0), N'(1,2) and O'(-1,1)
Next, we reflect M'N'O' the y-axis.
Note: When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite.
Therefore:
- Reflection of M'N'O' accross the y-axis gives: M"(-3,0), N"(-1,2) and O"(1,1).
Therefore, the sequence of transformations could be used to map triangle MNO onto M"N"O" is T(–2, 4) ry-axis.
The correct option is A.
Hi there!
Let there be two angles, ∠A and ∠B, that are supplementary to each other. Therefore:
∠A + ∠B = 180°
We can assign ∠B to be the greater angle. Assume ∠A has a measure of x°.
∠A = x°
∠B = x° + 30°
The sum is equal to 180°, so:
x° + (x° + 30°) = 180°
Solve for x°.
2x° + 30° = 180°
2x° = 150°
x° = 75°
Thus, ∠A = 75°.
Since ∠B is 30°, greater:
∠B = 75° + 30° = 105°.