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crimeas [40]
3 years ago
7

What is the pattern in the values as the exponents increase?

Mathematics
2 answers:
Troyanec [42]3 years ago
6 0

Divide the previous value by 3

brilliants [131]3 years ago
4 0

Answer:

Multiply the previous value by 3.

Step-by-step explanation:

The correct pattern in the values as the exponents increase is - Multiply the previous value by 3.

We can see, that 3^{-1} is \frac{1}{3}

And in the next step, 3^0 is \frac{1}{3}\times3=1

In the next step, 3^1 is 1\times3=3

In the last step, 3^2 is 3\times3=9

So, at each step, 3 is multiplied to the previous product/value.

Therefore, the correct answer is last option.

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If point B is at 0, then what are the values of points A and C?
Sunny_sXe [5.5K]

Answer:

Since the line is not scaled, then how do we know for sure.  But, we do know that point A is the opposite of point C.   For example, if C = 150, then A = -150

Step-by-step explanation:

Since the line is not scaled, then how do we know for sure.  But, we do know that point A is the opposite of point C.   For example, if C = 150, then A = -150

8 0
2 years ago
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umka2103 [35]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Joseph has saved $325. He wants to purchase a surfboard that costs $785. If he saves $12 each week from the money he earns mowin
Semmy [17]

Answer: 25.6 weeks

Step-by-step explanation:

He has saved $325 already so the amount left to purchase the surfboard is:

= 785 - 325

= $460

He saves $12 and $6 every week.

= $18.

Number of weeks left:

= 460/18

= 25.6 weeks

6 0
3 years ago
Find the values of the sine, cosine, and tangent for ZA C A 36ft B <br> 24ft
Reptile [31]
<h2>Question:</h2>

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = \frac{\sqrt{13} }{2},  cos A = \frac{\sqrt{13} }{3},  tan A = \frac{2 }{3}

b. sin A = 3\frac{\sqrt{13} }{13},  cos A = 2\frac{\sqrt{13} }{13},  tan A = \frac{3}{2}

c. sin A = \frac{\sqrt{13} }{3},  cos A = \frac{\sqrt{13} }{2},  tan A = \frac{3}{2}

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Answer:</h2>

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Step-by-step explanation:</h2>

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

<em>i. First calculate the value of the missing side AB.</em>

<em>Using Pythagoras' theorem;</em>

⇒ (AB)² = (AC)² + (BC)²

<em>Substitute the values of AC and BC</em>

⇒ (AB)² = (36)² + (24)²

<em>Solve for AB</em>

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = \sqrt{1872}

⇒ AB = 12\sqrt{13} ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of 12\sqrt{13} ft (43.27ft).

<em>ii. Calculate the sine of ∠A (i.e sin A)</em>

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = \frac{opposite}{hypotenuse}             -------------(i)

<em>In this case,</em>

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (i) as follows;</em>

sin A = \frac{24}{12\sqrt{13} }

sin A = \frac{2}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

sin A = \frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

sin A = \frac{2\sqrt{13} }{13}

<em>iii. Calculate the cosine of ∠A (i.e cos A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = \frac{adjacent}{hypotenuse}             -------------(ii)

<em>In this case,</em>

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (ii) as follows;</em>

cos A = \frac{36}{12\sqrt{13} }

cos A = \frac{3}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

cos A = \frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

cos A = \frac{3\sqrt{13} }{13}

<em>iii. Calculate the tangent of ∠A (i.e tan A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = \frac{opposite}{adjacent}             -------------(iii)

<em>In this case,</em>

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

<em>Substitute these values into equation (iii) as follows;</em>

tan A = \frac{24}{36}

tan A = \frac{2}{3}

6 0
3 years ago
(8+t)^3-6<br><br>t=2<br><br>(3 is an exponent)<br><br>The value is:
VikaD [51]

Answer:

994

Step-by-step explanation:

PEMDAS

Parentheses: 8+2 = 10

Exponents: 10^3 = 1000

Subtraction = 1000-6

= 994

8 0
3 years ago
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