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Cerrena [4.2K]
3 years ago
7

You select a marble from two different bags. You have a 30% chance of choosing a blue marble from the first bag and a 70% chance

of choosing a blue marble from the second bag. Design and use a simulation to estimate the probability that you choose a blue marble from both bags.
Mathematics
1 answer:
pogonyaev3 years ago
5 0

Answer:

50 percent is the average

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A: {-4, -2 -1, 2}<br> B: {-4, 4}<br> C: {-3, -2, 0, 2}<br> D: {-4, -2, -1, 0, -2}
Temka [501]

Answer:this is soooo compli

Step-by-step explanation:

5 0
2 years ago
Pls help me with this, i’ll give brainly
Nataly_w [17]

Answer:

shirts = 15 when pants = 6

15

Step-by-step explanation:

Try two others that are given

shirts / pants = 10 / 4 = 2.5

shirts / pants = 30/12 = 2.5

So shirts/pants = 2.5 = x/6

2.5 = x / 6                            Multiply by 6

2.5 * 6 = x

x = 15

8 0
2 years ago
LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Finding missing sides- similar triangles Algebraic practice )
Dimas [21]
143 / 6x+12 = 132 / 72
143 / 6x+12 = 11 / 6

crossmultiply:
66x + 132 = 858
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8 0
2 years ago
Read 2 more answers
Imani is selling T-shirts for a student council fund-raiser. She spent $100 on
Kruka [31]

Answer:

Step-by-step explanation:

the domain is gonna be ur x values and ur range is gonna be ur r(x) values

the domain has to do with the number of t-shirts.....and it can range from 0 to 25.......so it would be written as : [0,25]...include the brackets....not parenthesis...or all whole numbers from 0 to 25

the range has to do with the money made....and it can range from : -100 to 200....so it would be written as : [ -100,200] ..use brackets and not parenthesis.

3 0
3 years ago
A bag contains tickets numbered 1 through 5. Use the probability distribution to determine the probability of drawing an odd num
Makovka662 [10]

Answer:

The probability of drawing an odd numbered ticket is 60%.

Step-by-step explanation:

Odd numbered tickets:

Probability of one is 1/5 plus half of 1/5.

P(X = 1) = \frac{1}{5} + \frac{1}{10} = \frac{3}{10}

Probability of 3 is half of 1/5.

P(X = 3) = \frac{1}{10}

Probability of 5 is 1/5. So

P(X = 5) = \frac{1}{5}

Probability of drawing an odd numbered ticket:

p = P(X = 1) + P(X = 3) + P(X = 5) = \frac{3}{10} + \frac{1}{10} + \frac{1}{5} = \frac{4}{10} + \frac{2}{10} = \frac{6}{10} = 0.6

0.6*100% = 60%

The probability of drawing an odd numbered ticket is 60%.

3 0
3 years ago
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