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exis [7]
3 years ago
13

Can someone help me solve i will give 20 points

Mathematics
2 answers:
Otrada [13]3 years ago
7 0
  • Length of terrace: <u>5</u><u> </u><u>inches</u><u> </u> [ Given in figure ]

  • Width of terrace: <u>2</u><u> </u><u>inches</u><u> </u> [ Given in figure ]

  • Area of terrace : <u>1</u><u>0</u><u> </u><u>in</u><u>.</u><u>²</u> [ by calculation ]

<u>Solution:</u><u> </u>

Area of rectangle ( terrace ) = Length × width

= ( 5 × 2 ) in.²

= 10 in.²

HACTEHA [7]3 years ago
3 0

Answer:

l = 15 ft

w = 6 ft

A = 90 sq ft

Step-by-step explanation:

since the width is 2" then it is 6' per given info

the length can be found by using this proportion:  2"/6' = 5"/l

2l = 30

l = 15'

A = 15 x 6 = 90 sq ft

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8 0
2 years ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
Jena lives 1 mile from the school. She rides her bike at a speed of 4 miles per hour. If she leaves school at 2:30 p.m., what ti
Finger [1]

Answer:

I believe it's A

Step-by-step explanation:

Hope this helps!

8 0
2 years ago
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svetoff [14.1K]
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7 0
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What best describes the expression y over 4
Free_Kalibri [48]

Answer:

y/4

Step-by-step explanation:

b/c y is divided 4 so,y/4.

6 0
2 years ago
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