Answer:
The inline-block transforms the element to generate a block of box type which is laid out like an inline box. And in QuirksMode, the inline-block is being placed inline which is on the same line where the other content lies, however, it acts as a block. And the inline-block elements are quite the same as the inline element though you can have the padding as well as the margins that can be added on all the four sides. This is the only difference though, you will have to mention in the CSS code display:inline-block. They are very commonly used to make the horizontal navigation link.
Explanation:
Please check the answer section.
Answer:
port 80
Explanation:
port 80 is http. port 443 is https. so if you are trying to be a sneaky little person and eavesdrop on people, eavesdrop on port 80 not port 443 because port 80 is unsecured plaintext data transmission over websites
Answer:
1.Total debits must equal total credits
4.When posting to the accounts receivable account, you must specify a customer
5.You can post to multiple accounts receivable and/or accounts payable accounts in the same journal entry
Explanation:
1.
A Journal entry follows the concept of double-entry. In the double-entry principle, a debit entry equals a credit. After posting all the required entries total debits are equal to the total credits.
4.
The business makes sales to customers. Some sales are made on cash or some are made on credit. In the case of credit sales, the receivables are made. To record the credit sale entry we must specify the customer in the debit entry against the credit entry of sales.
5.
in recording the credit sales or purchases multiple receivable or payable accounts can be used and a single entry of sales of purchases can be posted against these accounts. For example
Journal Entry with multiple receivables accounts.
DR. Customers A $1,000
DR. Customers B $2,000
DR. Customers C $3,000
CR. Sales ______$6,000
Answer:
Following code will store the largest value in array parkingTickets in the variable mostTickets
mostTickets = parkingTickets[0];
for(int k = 0; k<parkingTickets.length; k++)
{
if(parkingTickets[i]>mostTickets)
{
mostTickets = parkingTickets[i];
}
}
Explanation:
In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.
Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.
If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.
This process is repeated for all elements in array.
Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.
Answer:
well you have to take classes or use easier systems like scratch
Explanation: