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SOVA2 [1]
2 years ago
6

Se desea constrir una barda utilizando block . las dimensiones de la barda son 25 m de largo y 2 m de altura . si se requieren 1

2 blocks para cada metro cuadrado de barda ¿ cuantos blocks se usaran en su construcción?​
respuesta urgente !!!
Mathematics
1 answer:
Andrew [12]2 years ago
3 0

Answer:

I don't understand the language

Step-by-step explanation:

am not form Paris

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13<br> 14 - 1<br> 7 +<br> 1<br> 2 = what??
Studentka2010 [4]

Answer:

36

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Solve the following systems b elemination show work and explain each step 3x + y = 13 4x - 3y = 13
Alika [10]

Answer:

x = 4

y = 1

Step-by-step explanation:

Here, we want to solve the system of equation using elimination method

We have this as follows;

3x + y = 13

4x- 3y = 13

Multiply equation 1 by 3

9x + 3y = 39

4x-3y = 13

Add the two equations

13x = 52

x = 52/13

x = 4

From equation 1;

3x + y = 13

y = 13-3x

y = 13-3(4)

y = 13-12 = 1

5 0
2 years ago
Give two reasons why an IT manager would consider using cloud software.
ludmilkaskok [199]

1. Cloud offers better insight.In a world awash in structured and, increasingly, unstructured data, 54% of leading organizations are using analytics to derive insights from big data, which helps them target customers and product opportunities more effectively. 

2. Cloud helps collaboration. Cloud allows work to be accessed from multiple devices and from anywhere, which in turns makes it much easier for teams to collaborate on shared data. 

5 0
3 years ago
24 less than 4 times a number is 60. what is the number?
kondaur [170]
Hey there! :D

Make an algebraic expression. 

Let the 'number' equal x. 

4x-24= 60

Add 24 on both sides. 

4x= 84

Divide both sides by 4. 

x=21

The number is 21. 

I hope this helps!
~kaikers 
8 0
3 years ago
3x+-2y=-6<br> 5x-2y=7<br> how do i solve this Elimination pls
tatuchka [14]

Answer:

x=\frac{13}{2}, y=\frac{51}{4}

Step-by-step explanation:

We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}

Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}

4 0
3 years ago
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