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3 years ago

Which of the following fractions is equivalent to 5/6 10/16 7/8 2/3 15/18

2 answers:

8 0

5/6 * 3/3 = 15/18......if u take ur fraction and multiply it by the same numerator and denominator, the result will be an equivalent fraction.

example :
if I multiplied 5/6 * 2/2 = 10/12...this is also equivalent...
5/6 * 4/4 = 20/24....and this is equivalent as well.

so ur answer is 15/18

frutty [35]3 years ago

5 0

Go on your calculator and type in 5 divided by 6. Go through your answers and do the same thing. Which ever one equals the same decimal is your answer.

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andre [41]

It's C first find 3/5 of the horoziotal

3 0

3 years ago

Please help mee you will get 100 points

professor190 [17]

Answer:

Equation: 15 - f = n

Answer: n = 9

Step-by-step explanation:

The question is asking to write the equation. The equation would be

"15 - f = n" where f shirts folded

n = shirts remaining to fold

Then the question has gave us the value of f and has told us to solve it. Below is the solution.

15 - 6 = n

=> n = 9

Therefore, there is 9 shirts remaining after 6 of them are folded.

What did we solve?

We wrote our equation and solved what was required in the question.

I hoped this helped.

If possible... May I have brainliest :)

8 0

3 years ago

Read 2 more answers

Can you very be kind and answer

Lera25 [3.4K]

area of a circle is PI x r^2

2 = d/2 = 5.4/2 = 2.7 cm

using 3.14 for PI

3.14 x 2.7^2 = 22.89 square inches

360 degree in a circle, shaded area is 180 degree, which is 50%

so 22.89 x .5 = 11.45 cm^2

4 0

3 years ago

Solve the expression: x = 5, y = 8. x² - 3y =

Fed [463]

Answer:

x^2-3y

5^2-3*8

25-24

Step-by-step explanation:

3 0

3 years ago

A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and

natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: $E=k\frac{q}{r^{2} }$ ; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: $p=\frac{q}{A}$ ; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: $S=4\pi r^{2}$ ; which gives us the surface of a sphere.