Answer:
(i) 208 cm from the pivot
(ii) Move further from the pivot
Explanation:
(i) Sum of the moments about the pivot of the seesaw is zero.
∑τ = Iα
(50 kg) (10 N/kg) (2.5 m) + (60 kg) (10 N/kg) x = 0
1250 Nm + 600 N x = 0
x = -2.08 m
Kenny should sit 208 cm on the other side of the pivot.
(ii) To increase the torque, Kenny should move away from the pivot.
Answer:
The trouble that the most recent experiment, Borexino, have to overcome was that
neutrinos hardly interact with matter and so radioactive decay of ant material inside the detector could look exactly like a neutrino interaction too
Answer:
1.41s
5.95m/s
0.2746m
Explanation:
The time period
T = 1/f
= 1/0.709s
= 1.41 seconds
We have
T = 2π√l/g
T² = 4π²l/g
g = 4π²l/T²
g = 4x3.14²x0.300/1.41²
g = 5.95m/s² this is the acceleration due to gravity.
Then the time period of the glide
T2 = 2π√m/k
Length of pendulum = l
Time period T
T2 = 2π√l/g
Then T1 = T2
2π√m/k = 2π√l/g
M/k = l/g
L = g.m/k
L = 5.95x0.450/9.75
L = 0.2746
This must be the length of the simple pendulum
The answer is "156.6 m/s".
This is how we calculate this;
-N + mg = ma = mv²/r
For "weightlessness" N = 0, so
0 = mg - mv²/r
g - v²/r = 0
v =√( gr)
g = 9.8 and r = 2.5km = 2500 m
v = √(9.8 x 2500)
= 156.6 m/s
Answer:
1) Mass of the grain is
.
2) 0.08901 kg of sand would have surface area equal the surface area of the cube.
Explanation:
1) Radius of the grain,r = 64.8 µm =
Volume of the sphere =
Volume of the grain of a sand:


Density of a grain of sand = 
Mass of a grain of a sand = M


Mass of the grain is
.
2) Surface are of sphere: 
Surface area of a grain:


Length of the cube = a = 0.514 m
Total surface area of cube ,A'= 

let the number grains with area equal to total surface area of cube be x.


Volume of x number of grains :V'



Mass of
of sandL:
=
0.08901 kg of sand would have surface area equal the surface area of the cube.