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garik1379 [7]
3 years ago
7

What do you mean by pressure of a liquid? Write its Sl unit.​

Physics
1 answer:
Andre45 [30]3 years ago
6 0

Explanation:

Pressure of a liquid :

Liquids also exert pressure as that in case of solids. We can understand it as the fact that it is impossible to hammer a nail with liquid. That's why liquid exert pressure on its surface. The formula for the pressure in liquid is given by :

P=\rho gh

Where

\rho = density of liquid

g = acceleration due to gravity

h = height

The SI init of pressure is Pascal and it is dented by Pa.

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Kenny and Candy decided to sit on a see-saw while visiting a local play park. Candy, of mass
pochemuha

Answer:

(i) 208 cm from the pivot

(ii) Move further from the pivot

Explanation:

(i) Sum of the moments about the pivot of the seesaw is zero.

∑τ = Iα

(50 kg) (10 N/kg) (2.5 m) + (60 kg) (10 N/kg) x = 0

1250 Nm + 600 N x = 0

x = -2.08 m

Kenny should sit 208 cm on the other side of the pivot.

(ii) To increase the torque, Kenny should move away from the pivot.

4 0
4 years ago
Observing neutrinos from the Sun is an important way to check the fusion rate, but it can be very tough to build a machine that
Vika [28.1K]

Answer:

The trouble that the most recent experiment, Borexino, have to overcome was that

neutrinos hardly interact with matter and so radioactive decay of ant material inside the detector could look exactly like a neutrino interaction too

5 0
3 years ago
On an alien planet, a simple pendulum of length 0.300 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Fin
sweet [91]

Answer:

1.41s

5.95m/s

0.2746m

Explanation:

The time period

T = 1/f

= 1/0.709s

= 1.41 seconds

We have

T = 2π√l/g

T² = 4π²l/g

g = 4π²l/T²

g = 4x3.14²x0.300/1.41²

g = 5.95m/s² this is the acceleration due to gravity.

Then the time period of the glide

T2 = 2π√m/k

Length of pendulum = l

Time period T

T2 = 2π√l/g

Then T1 = T2

2π√m/k = 2π√l/g

M/k = l/g

L = g.m/k

L = 5.95x0.450/9.75

L = 0.2746

This must be the length of the simple pendulum

8 0
3 years ago
In order to simulate weightlessness for astronauts in training, they are flown in a vertical circle. if the passengers are to ex
sleet_krkn [62]
The answer is "156.6 m/s".

This is how we calculate this;

-N + mg = ma = mv²/r

For "weightlessness" N = 0, so

0 = mg - mv²/r 

g - v²/r = 0 

v =√( gr)
g = 9.8 and r = 2.5km = 2500 m

v = √(9.8 x 2500)

= 156.6 m/s
8 0
3 years ago
Fine grains of beach sand are assumed to be spheres of radius 64.8 µm. These grains are made of silicon dioxide which has a dens
Nutka1998 [239]

Answer:

1) Mass of the grain is 2.9632\times 10^{-9} kg.

2) 0.08901 kg of sand would have surface area equal the surface area of the cube.

Explanation:

1) Radius of the grain,r = 64.8 µm =6.48\times 10^{-5}m

Volume of the sphere =\frac{4}{3}\pi r^3

Volume of the grain of a sand:

V=\frac{4}{3}\times \pi r^3=\frac{4}{3}\times 3.14\times (6.48\times 10^{-5} m)^3

V=1.1397\times 10^{-12} m^3

Density of a grain of sand = d=2600 kg/m^3

Mass of a grain of a sand = M

d=2600 kg/m^3=\frac{M}{1.1397\times 10^{-12} m^3}

M=2.9632\times 10^{-9} kg

Mass of the grain is 2.9632\times 10^{-9} kg.

2) Surface are of sphere: 4\pi r^2

Surface area of a grain:

A=4\times 3.14\times (6.48\times 10^{-5}m)^2

A=5.2766\times 10^{-8} m^2

Length of the cube = a = 0.514 m

Total surface area of cube ,A'= 6a^2

A'=6\times (0.514 m)^2=1.5851 m^2

let the number grains with area equal to total surface area of cube be x.

A'=A\times x

x=\frac{1.5851 m^2}{5.2766\times 10^{-8} m^2}=3.003\times 10^7

Volume of x number of grains :V'

V'=V\times x

V= 1.1397\times 10^{-12} m^3\times 3.003\times 10^7

V'=3.4236\times 10^{-5} m^3

Mass of 3.4236\times 10^{-5} m^3 of sandL:

=3.4236\times 10^{-5} m^3\times 2600 kg/m^3=0.08901 kg

0.08901 kg of sand would have surface area equal the surface area of the cube.

8 0
3 years ago
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