All categories

2 years ago

A shop-vac is capable of pulling in air at a rate of 210 ft^3/min. what is the rate of the vacuum's air flow in l/s?

Physics

1 answer:

Nadya [2.5K]2 years ago

3 0

The correct answer is 99.06 .

Since we know that,

1 ft = 12 inches, (1ft)3 = (12)3inches3

& 1 inch = 2.54 cm , (1 inch)3 = (2.54)3cm3

& 1 cm3 = 1ml,

&(1 ml)/1000 = 1L, so (1cm3)/1000 = 1L.

& 1 min. = 60 sec.

Now, 1ft3 = (12)3x(2.54)3/(1000) L

and 1 min = 60 sec

So, 1ft3/min = (12)^3x(2.54)^3/(1000)x(60) L/s

Hence 210 ft3/min = 210x(12^)3x(2.54)^3/(1000)x(60).

= 99.06.

Learn more about rate of the vacuum's air flow here :-

brainly.com/question/24641042

#SPJ4

You might be interested in

A motorcycle moving 18.8 m/s has<br> 57800 J of KE. What is its mass?

Brums [2.3K]

Answer:

m = 327.07 kg

Explanation:

Given that,

Kinetic energy of a motorcycle, E = 57800 J

Velocity of the motorcycle, v = 18.8 m/s

We need to find the mass of the motorcycle. The kinetic energy of an object is given by :

$E=\dfrac{1}{2}mv^2$

m is mass

$m=\dfrac{2E}{v^2}\\\\m=\dfrac{2\times 57800 }{(18.8)^2}\\\\m=327.07\ kg$

So, the mass of the motorcycle is 327.07 kg.

8 0

3 years ago

What 3 types of metals have magnetic properties

satela [25.4K]

Ferromagnetic, paramagnetic, and diamagnetic

6 0

3 years ago

Read 2 more answers

You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state

Aleks04 [339]

Explanation:

It is given that,

Height of the building, h = 44 m

Initial horizontal velocity, $u_x=ucos\theta=8.6\ m/s$

Initial vertical velocity, $u_y=usin\theta=10.5\ m/s$

It can be assumed to find the maximum height of the projectile and time taken to reach the maximum height.

The formula for the maximum height is given by :

$H=\dfrac{(u\ sin\theta)^2}{2g}$

g is the acceleration due to gravity

$H=\dfrac{(10.5)^2}{2\times 9.8}=5.625\ m$

The total maximum height, h' = h + H

$h'=44+5.625=49.625\ m$

The formula for the time of flight is given by :

$t_{max}=\dfrac{u\ sin\theta}{g}$

$t_{max}=\dfrac{10.5}{9.8}=1.07\ s$

Hence, this is the required solution.

3 0

3 years ago

What is the efficiency of a machine if your work on the machine is 1200 j and the machines output work is 300 j?

inysia [295]

Answer:

The efificiency is 0,25 of the machine (25%). See the explanation below

Explanation:

We calculate the efficiency with this formula:

Efficiency = energy obtained/energy supplied= 300 Joule/1200 Joule

Efficiency= 0,25

Efficiency(%) = 0,25 x100 = 25%

7 0

3 years ago

Read 2 more answers

Ferns spread spores instead of seeds, and some ferns eject the spores at surprisingly high speeds. One species accelerates 1.4 μ

marta [7]

Answer:

Impulse is $6.3*10^{-9}\:N \cdot s$

The average force is $6.3*10^{-6} N$

Explanation:

When a mass $m$ undergoes a change in velocity $\Delta v$ , its impulse $I$ is

$I =m\Delta v$

and if a force $F$ is acting for time $t$ , then the impulse $I$ is given by

$I=F*t$

Now the mass of the spores in kg is

$m=1.4*10^{-6}g*\frac{10^{-3}kg}{g}=1.4*10^{-9}kg$

we calculate the impulse from the first formula:

$I =m\Delta v =(1.4*10^{-9}kg)(4.5\frac{m}{s} )=6.3*10^{-9}N\cdot s$

$\boxed{I=6.3*10^{-9}\:N \cdot s}$

Now that we have impulse, we calculate the average force on the spore from the second formula:

$F=\frac{I}{t} =\frac{6.3*10^{-9}}{1*10^{-3}s}=6.3*10^{-6} N$

$\boxed{F=6.3*10^{-6} N}$

5 0

3 years ago