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Tpy6a [65]
2 years ago
11

Find the zeros of the expression

Mathematics
2 answers:
nirvana33 [79]2 years ago
6 0
The answer is B. 4,-5,3
DiKsa [7]2 years ago
4 0
The answer is 4, -5, 3
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What equivalent expression is equal to this<br><br><br>(2^-4*2^-3)^5
Katen [24]

(2^{-4} \cdot z^{-3})^5=2^{-4 \cdot 5} \cdot z^{-3 \cdot 5}=2^{-20} \cdot z^{-15}

⇒ \frac{1}{2^{20} \cdot z^{15}}


8 0
3 years ago
A triangle has side lengths of (2.4b+3.1)(2.4b+3.1) centimeters, (5.9b-9.7)(5.9b−9.7) centimeters, and (5.9c-5.3)(5.9c−5.3) cent
Masja [62]
101010100110011010101010101

7 0
3 years ago
54 students fit on a bus. There are 125
vfiekz [6]

Answer: 3 buses

Step-by-step explanation: If 54 students fit on a bus, and 125 students are in 8th grade,

You should divide.

125 divided by 54 is 2.31...

we can't have 2.31... buses, so we say 3 buses.

3 0
1 year ago
Read 2 more answers
Doña Gertrudis recolecta en promedio 75 litros de leche de cabra por día y utiliza alrededor de 5 litros para hacer un kilogramo
Nimfa-mama [501]

Answer:

825 pesos a day on average

1 dozen weight = 2.4 kg

Step-by-step explanation:

In ENGLISH:

Doña Gertrudis collects on average 75 liters of goat milk per day and uses around 5 liters to make one kilogram of cheese. The cheeses he makes weigh 200 grams each and he sells them for 132 pesos a dozen. How much money do you get per day on average from the sale of your cheeses? How many kilograms does the dozen cheeses weigh?

<u>Solution:</u>

75 Liters / 5 Liters = 15

15 * 1 kg = 15 kg of cheese per day

15kg in grams is 15*1000 = 15,000 grams

Each cheese block is 200 grams, so number of blocks of cheese:

15,000/200 = 75 blocks of cheese

1 dozen (12) = 132 pesos, so 1 would be:

132/12 = 11 pesos PER BLOCK

SO, 75 blocks of cheese = 75 * 11 = <u>825 pesos (per day on average)</u>

<u></u>

Dozen cheese weight in kg,

200 grams * 12 = 2400 grams

In kg,

2400/1000 = <u>2.4 kg</u>

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%
Llana [10]

a) The given function is

f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}

The domain refers to all values of x for which the function is defined.

The function is defined for

x^4+x^3-4x^2-4\ne0

This implies that;

x\ne -2.69,x\ne 1.83

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

x^4+x^3-4x^2-4=0

This implies that;

x= -2.69,x=1.83

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

\frac{x^2-4}{x^4+x^3-4x^2-4}=0

\Rightarrow x^2-4=0

x^2=4

x=\pm \sqrt{4}

x=\pm2

The roots are x=-2,x=2

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

x=0 into the function

f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}

f(0)=\frac{-4}{-4}=1

e) to find the horizontal asypmtote, we take limit to infinity

lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0

The horizontal asymtote is y=0

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is  at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0
3 years ago
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