Q1=3 Q2[median]=12 Q3=14 and the IQR is 11
Perpendicular bisector theorem
Answer:
read your username :)
Step-by-step explanation:
Answer:
x ≤ 3
Step-by-step explanation:
2(4+2x) ≥ 5x+5 (by PEDMAS, expand parentheses first)
4(2) + 2x(2) ≥ 5x + 5
8 + 4x ≥ 5x + 5 (subtract 8 from each side)
4x ≥ 5x + 5 - 8
4x ≥ 5x - 3 (subtract 5x from both sides)
4x -5x ≥ - 3
-x ≥ - 3 (multiply both sides by -1, remember to flip the inequality when multiplying both sides by a negative number)
x ≤ 3
One way to find the least common multiple of two numbers is to first list the prime factors of each number.
8 = 2 x 2 x 2
Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.
2: three occurrences
3: one occurrence
So, our LCM should be
2 x 2 x 2 x 3 = 24.
So, Marco can buy, at the very least, 24 beads of each color to have equal colors of beads.
