=(-4/5)^2 * -3/50
square -4/5 first; remember -4/5^2 is the same as -4/5 * -4/5
=(-4/5 * -4/5) * -3/50
multiply -4 numerators; multiply 5 denominators
=(-4 * -4)/(5 * 5) * -3/50
=16/25 * -3/50
multiply numerators 16 & -3; multiply denominators 25 & 50
=(16 * -3)/(25 * 50)
= -48/1250
simplify by 2
= -24/625 (or -0.0384)
ANSWER: -24/625 (or -0.0384)
Hope this helps! :)
Hmmm...
We have to divide 12 by 8, since we need to see how 8 students will share 12 slices.
12/8=1 and 1/2
So, each student can have a slice and a half, but since we aren't allowed to cut the slices...
We can let each student have one slice, with 4 left over, so...
Every student can have one slice, and then half can have a second slice :)!
I'm not sure if that is what was meant by the question, but that was all I could think of.
I hope I helped! :)
Answer:
4/3
Step-by-step explanation:
9-1/8-2=
8/6=4/3
Answer:
n° = 62°
p° = 62°
q° = 118°
v° = 84°
w° = 138°
Step-by-step explanation:
angle ABC is 118°
so
m° + 118° = 180
m° = 180° - 118°
m° = 62°
n° = m° = 62° (corresponding angles are equal since AB is parallel to DC, and BC)
p° = n° = 62° (vertical angles are equal)
q° + n° = 180° (linear pair angles)
q° + 62° = 180°
q° = 180° - 62°
q° = 118°
v° + 96° = 180° (linear pair angles)
v° = 180° - 96°
v° = 84°
w° + 42° = 180 (linear pair angles)
w° = 180° - 42°
w° = 138°
Answer:
a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)
Step-by-step explanation:
Let's solve by separating variables:
a) x’=t–sin(t), x(0)=1
Apply integral both sides:
where k is a constant due to integration. With x(0)=1, substitute:
Finally:
b) x’+2x=4; x(0)=5
Completing the integral:
Solving the operator:
Using algebra, it becomes explicit:
With x(0)=5, substitute:
Finally:
c) x’’+4x=0; x(0)=0; x’(0)=1
Let 
be the solution for the equation, then:
Substituting these equations in <em>c)</em>
This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>
![x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)](https://tex.z-dn.net/?f=x%3De%5E%7B%5Calpha%20t%7D%5BAsin%5Cbeta%20t%2BBcos%5Cbeta%20t%5D%5C%5C%5C%5Cx%3De%5E%7B0%7D%5BAsin%28%282%29t%29%2BBcos%28%282%29t%29%5D%5C%5C%5C%5Cx%3DAsin%28%282%29t%29%2BBcos%28%282%29t%29)
Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:
Finally:
