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Y_Kistochka [10]
3 years ago
13

Evaluate ((6+2) ÷ (10-8) +10) ∙ 5

Mathematics
1 answer:
miskamm [114]3 years ago
5 0
You can do that on photo math
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The vertex would be (-2,4)
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Solve the system of equations and choose the correct answer from the list of options. (4 points)
Viefleur [7K]

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Negative 8 over 5 comma negative 6 over 5

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Janae drew point A located at (-2,5), and point located at (6, -1). What is the x-coordinate of point B that bisects AC? ​
Sphinxa [80]

Answer:

The x coordinate is 2

Step-by-step explanation:

Given

A = (-2,5)

C = (6,-1)

Required

Determine the x coordinate of B

Since B is the bisector of AC, then B is the midpoint and will be calculated using;

B(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})

Considering the x coordinates alone;

x  = \frac{x_1 + x_2}{2}

Where

(x_1,y_1) = (-2,5)    and     (x_2,y_2) = (6,-1)

Substitute values for x1 and x2

x = \frac{-2 + 6}{2}

x = \frac{4}{2}

x = 2

<em>Hence;</em>

<em>The x coordinate is 2</em>

6 0
3 years ago
6x(14-6)-3 exopent 2
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Answer:

39

Step-by-step explanation:

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The graph of the relation T is shown below.
blsea [12.9K]

Answer:

The sets of the domain and the range of T are, respectively:

Dom \{T\} =\{-3,0,3\}

Ran\{T\} = \{-4.-3,2,3\}

Step-by-step explanation:

The values of the relation T that belongs to the domains correspond with the values on the x-axis and associated with the given points, whereas the range corresponds with the respective values of the y-axis. Let T = \{(x,y)|(-3,3),(3,2),(0,-3),(3,-4)\}

The sets of the domain and the range of T are, respectively:

Dom \{T\} =\{-3,0,3\}

Ran\{T\} = \{-4.-3,2,3\}

4 0
3 years ago
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