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Y_Kistochka [10]
3 years ago
13

Evaluate ((6+2) ÷ (10-8) +10) ∙ 5

Mathematics
1 answer:
miskamm [114]3 years ago
5 0
You can do that on photo math
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PLEASEEEE
Jobisdone [24]
<h3>Answer:  9.4 feet</h3>

Work Shown:

sin(angle) = opposite/hypotenuse

sin(22) = x/25

x = 25*sin(22)

x = 9.3651648353978

x = 9.4

Your calculator needs to be in degree mode. One way to check is to compute sin(30) and you should get 0.5 or 1/2.

3 0
2 years ago
What is the solution to 2x^2+8=x^2-16?
KIM [24]
X= 2i(square root of 6), -2i(square root of 6)
7 0
3 years ago
5 times x to the one fourth power
skelet666 [1.2K]

Answer:

<em>5</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>4</em>

<em>X </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>u</em><em> </em><em>if </em><em>yes</em><em> </em><em>then</em><em> </em><em>foll</em><em>ow</em><em> me</em>

3 0
3 years ago
This month, Chun’s office produced 690 pounds of garbage. Chun wants to reduce the weight of garbage produced to 85% of the weig
Effectus [21]
Chun wants to <span>reduce the weight of garbage produced to 85% of the weight produced this month. 
This means that, Chun's garbage weight next month should be equal to 85% of his garbage weight this month.

Translating this into an equation, we will find that:
garbage weight next month = 85% of garbage weight this month
garbage weight next month = 0.85 * garbage weight this month
garbage weight next month = 0.85*690 
garbage weight next month = 586.5 pounds

Based on the above calculations, his target weight for the garbage next month is </span>586.5 pounds
8 0
3 years ago
15. The length of each edge of a regular tetrahedron,
grigory [225]

Slant height of tetrahedron is=6.53cm

Volume of the tetrahedron is=60.35\mathrm{cm}^{3}

Given:

Length of each edge a=8cm

To find:

Slant height and volume of the tetrahedron

<u>Step by Step Explanation: </u>

Solution;

Formula for calculating slant height is given as

Slant height=\sqrt{\frac{2}{3}} a

Where a= length of each edge

Slant height=\sqrt{\frac{2}{3}} \times 8

                     =\sqrt{0.6667} \times 8

                     =0.8165 \times 8=6.53cm

Similarly formula used for calculating volume is given as

Volume of the tetrahedron=\frac{a^{3}}{6 \sqrt{2}}

Substitute the value of a in above equation we get

Volume=\frac{8^{5}}{6 \sqrt{2}}

            =\frac{512}{6 \sqrt{2}}

            =\frac{512}{6 \times 1.414}

Volume=512 / 8.484=60.35\mathrm{cm}^{3}

Result:

Thus the slant height and volume of tetrahedron are 6.53cm and 60.35\mathrm{cm}^{3}

7 0
3 years ago
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