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3 years ago

M Explain why this is true PLEASE HELP!!!

Mathematics

1 answer:

borishaifa [10]3 years ago

3 0

Answer:

The given statement is true because the person they did their steps correctly

a) Locate a point C so that ABC is a right triangle with m ACB ∠ = ° 90 and the measure of one of the acute angles in the triangle is 45° .

b) Locate a point D so that ABD is a right triangle with m ADB ∠ = ° 90 and

the measure of one of the acute angles in the triangle is30° .

c) Locate a point E so that ABE is a right triangle with m AEB ∠ = ° 90 and

the measure of one of the acute angles in the triangle is15° .

d) Find the distance between point C and the midpoint of segment AB .

Repeat with points D and E.

e) Suppose F is a point on the graph so that ABF is a right triangle

withm AFB ∠ =° 90 . Make a conjecture about the point F.

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What is the answer?

stealth61 [152]

Answer:

Step-by-step explanation:

$(\frac{1}{9})(\frac{2}{3})^x=(\frac{12}{243})\\(\frac{2}{3})^x=\frac {12}{243} \times \frac {9}{1}=\frac{4}{9}=(\frac{2}{3})^2 \\x=2$

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3 years ago

Read 2 more answers

The area of a circle is 55.44 cm2. Find its circumference.

IrinaK [193]

Answer:

Circle

Solve for circumference

C≈26.39cm

A Area

55.44

cm²

8 0

3 years ago

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

First case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

Second case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago

Loretta uses 1/6 bag of

joja [24]

you would take 3/4 and multiply it by six or to make it easyier just take the three and add it six times which is 18 thn you take 18 and divide it by 4 which you cant evenly so take 18/4 and reduce it which is 4 cup and 2/4 or 1/2

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3 years ago

I need a little bit of help on this. Thought I knew how to do it

Mariana [72]

Answer:

U should do like this...

6 0

3 years ago