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Lunna [17]
3 years ago
15

What is 0.00000349462 in fraction form

Mathematics
2 answers:
Komok [63]3 years ago
6 0
174,731/50,000,000,000
harkovskaia [24]3 years ago
5 0

Answer:

0.03

Step-by-step explanation:

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You have $6 and earn $0.50 for each cup of orange juice you sell. Write an equation in two variables that represents the total a
natta225 [31]
A = 0.50j + 6.......u r correct

he started with 6....and he is selling each cup (j) for 0.50

so lets say he sold 10 cups...u would sub in 10 for j
A = 0.50(10) + 6
A = 5 + 6
A = 11......and he would have $ 11
6 0
3 years ago
Please help, ASAP. Thank you <3
Mumz [18]
48 I believe is the right answer
5 0
3 years ago
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A twelve-sided die with sides labeled through will be rolled once. Each number is equally likely to be rolled. What is the proba
FromTheMoon [43]

<em>Complete Question:</em>

<em>A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled, what is the probability of rolling a number greater than 10?</em>

Answer:

P(T) = \frac{1}{6}

Step-by-step explanation:

Given

Number of Sides = 12

Required

Probability of obtaining a side greater than 10

We start by listing out the sample space;

S = \{1,2,3,4,5,6,7,8,9,10,11,12\}

n(S) = 12

Next, we list out digits greater than 10; Represent this with T

T = \{11,12\}

n(T) = 2

Probability of T is calculated as follows;

P(T) = \frac{n(T)}{n(S)}

P(T) = \frac{2}{12}

Divide the numerator and denominator by 2

P(T) = \frac{1}{6}

<em>Hence, the required probability is </em>\frac{1}{6}<em />

8 0
3 years ago
How many solutions does the following equation have?<br> -15y+7+17y=2y+70−15y+7+17y=2y+70
Maru [420]
It has one solution Bc there is only one variable
7 0
3 years ago
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A grid has lines at 90-degreree angles. There are 12 lines in one direction and 9 lines in the other direction. Lines that are p
denis-greek [22]

Answer:

70

Step-by-step explanation:

Given that:

There are twelve (12) lines in a direction and another nine 9 lines in another direction.

If we draw the above illustration out, we will realize that we will have 11 squares by 8 squares.

i.e these 11 squares are 11 inches apart.

Hence, the length of their grid = 11  inches × 11 inches = 121  inches²

Thus, for 12 in by 12 in tiles; we will have:

= \dfrac {121}{12}

= 10 \dfrac{1}{12}

This implies that there are 10 files with just \dfrac{1}{2} inch gap in length.

Similarly, for 8 squares and 11 inches apart;

The width = 8 inches × 11 inches = 88 inches²

Thus; the 12 in tiles needed = \dfrac{88}{12}

= 7 \dfrac{1}{3}

It signifies that there are 7 tiles with \dfrac{1}{3} inch gap in width.

Thus, the least number of tiles required = 10 × 7 = 70

5 0
3 years ago
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