Answer:
the answer is 1100
Step-by-step explanation:
you will do... 5500*20/100
Answer:
QR=11
Step-by-step explanation:
Answer: x = 55/2
Step-by-step explanation: (x)(2) (-3)(2) = 49 2x-6+6 = 49+6 2x/2 = 55/2 x = 55/2
I know that my answer isn't a choice for one of the values of x but that's the result that I got when I solved (x–3)2 = 49.
A decagon does not necessarily have any pairs of parallel sides. A regular decagon, however, would have five pairs of parallel sides.
Answer with Step-by-step explanation:
We are given that
A=4i-2j+4k
B=-4i+3k
![\mid A\mid=\sqrt{4^2+(-2)^2+4^2}=6](https://tex.z-dn.net/?f=%5Cmid%20A%5Cmid%3D%5Csqrt%7B4%5E2%2B%28-2%29%5E2%2B4%5E2%7D%3D6)
![mid B\mid=\sqrt{3^2+(-4)^2}=5](https://tex.z-dn.net/?f=mid%20B%5Cmid%3D%5Csqrt%7B3%5E2%2B%28-4%29%5E2%7D%3D5)
![\hat{A}=\frac{A}{\mid A\mid}](https://tex.z-dn.net/?f=%5Chat%7BA%7D%3D%5Cfrac%7BA%7D%7B%5Cmid%20A%5Cmid%7D)
![\hat{A}=\frac{4i-2j+4k}{6}=\frac{2}{3}i-\frac{1}{3}j+\frac{2}{3}k](https://tex.z-dn.net/?f=%5Chat%7BA%7D%3D%5Cfrac%7B4i-2j%2B4k%7D%7B6%7D%3D%5Cfrac%7B2%7D%7B3%7Di-%5Cfrac%7B1%7D%7B3%7Dj%2B%5Cfrac%7B2%7D%7B3%7Dk)
![\hat{B}=\frac{-4i+3k}{5}=\frac{-4}{5}i+\frac{3}{5}k](https://tex.z-dn.net/?f=%5Chat%7BB%7D%3D%5Cfrac%7B-4i%2B3k%7D%7B5%7D%3D%5Cfrac%7B-4%7D%7B5%7Di%2B%5Cfrac%7B3%7D%7B5%7Dk)
Sum of unit vectors=![\hat{A}+\hat{B}](https://tex.z-dn.net/?f=%5Chat%7BA%7D%2B%5Chat%7BB%7D)
Sum of unit vectors=![\frac{2}{3}i-\frac{1}{3}j+\frac{2}{3}k+\frac{-4i+3k}{5}=\frac{-4}{5}i+\frac{3}{5}k](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7Di-%5Cfrac%7B1%7D%7B3%7Dj%2B%5Cfrac%7B2%7D%7B3%7Dk%2B%5Cfrac%7B-4i%2B3k%7D%7B5%7D%3D%5Cfrac%7B-4%7D%7B5%7Di%2B%5Cfrac%7B3%7D%7B5%7Dk)
Sum of unit vectors=![\frac{-2}{15}i-\frac{1}{3}j+\frac{19}{15}k](https://tex.z-dn.net/?f=%5Cfrac%7B-2%7D%7B15%7Di-%5Cfrac%7B1%7D%7B3%7Dj%2B%5Cfrac%7B19%7D%7B15%7Dk)
![\mid \hat{A}+\hat{B}\mid=\sqrt{(\frac{-2}{15})^2+(\frac{1}{3})^2+(\frac{19}{15})^2}](https://tex.z-dn.net/?f=%5Cmid%20%5Chat%7BA%7D%2B%5Chat%7BB%7D%5Cmid%3D%5Csqrt%7B%28%5Cfrac%7B-2%7D%7B15%7D%29%5E2%2B%28%5Cfrac%7B1%7D%7B3%7D%29%5E2%2B%28%5Cfrac%7B19%7D%7B15%7D%29%5E2%7D)
![\mid \hat{A}+\hat{B}\mid=1.32](https://tex.z-dn.net/?f=%5Cmid%20%5Chat%7BA%7D%2B%5Chat%7BB%7D%5Cmid%3D1.32)
![\theta_1=Cos^{-1}(\frac{A\cdot B)}{\mid A\mid \mid B\mid}](https://tex.z-dn.net/?f=%5Ctheta_1%3DCos%5E%7B-1%7D%28%5Cfrac%7BA%5Ccdot%20B%29%7D%7B%5Cmid%20A%5Cmid%20%5Cmid%20B%5Cmid%7D)
![\theta_1=cos^{-1}(\frac{-4}{30})=97.6^{\circ}](https://tex.z-dn.net/?f=%5Ctheta_1%3Dcos%5E%7B-1%7D%28%5Cfrac%7B-4%7D%7B30%7D%29%3D97.6%5E%7B%5Ccirc%7D)
![\theta_2=cos^{-1}(\frac{(Sum\;of\;unt\;vectors\cdot A)}{\mid sum\mid \mid A\mid }](https://tex.z-dn.net/?f=%5Ctheta_2%3Dcos%5E%7B-1%7D%28%5Cfrac%7B%28Sum%5C%3Bof%5C%3Bunt%5C%3Bvectors%5Ccdot%20A%29%7D%7B%5Cmid%20sum%5Cmid%20%5Cmid%20A%5Cmid%20%7D)
![\theta_2=cos^{-1}(\frac{78}{15\cdot 2\cdot 1.32\cdot 6})=49^{\circ}](https://tex.z-dn.net/?f=%5Ctheta_2%3Dcos%5E%7B-1%7D%28%5Cfrac%7B78%7D%7B15%5Ccdot%202%5Ccdot%201.32%5Ccdot%206%7D%29%3D49%5E%7B%5Ccirc%7D)
![\frac{1}{2}\theta_1=\frac{1}{2}(97.6)=48.8\sim 49^{\circ}=\theta_2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctheta_1%3D%5Cfrac%7B1%7D%7B2%7D%2897.6%29%3D48.8%5Csim%2049%5E%7B%5Ccirc%7D%3D%5Ctheta_2)
Hence, proved.