There's this all that's called photomath. it should get I for you
Answer:
3
Step-by-step explanation:
subtract 1 from 13 divide the number by 4
If the domain of <span>y = 2x - 2 is {1, 2, 3}, then the range has only three values:
2(1)-2=0
2(2)-2=2
2(3)-2=4
The range is {0,2,4}.</span>
Unsure of whether this is a composite function or not. It does look like you've multiplied f(x) and g(x) together.
Looking at <span>-30x2 - 9x + 12, we see immediately that this is a polynomial function. Because of that, the domain is the set of all real numbers. The graph of this poly opens down, so the max value is at the vertex, x = -b / (2a).
Here a= -6 and b= -9, so this x-value is -(-9) / (2*(-6)), or x = 9/12, or x = 3/4.
By subst. 3/4 for x in the poly., we find that the max y value is 4.83. Thus,the rante is (-infinity, 4.83].</span>
The answer is: " y − 1 = - 3(x + 2) " .
__________________________________________________________
Explanations:
__________________________________________________________
<u>Note</u>: The "point-slope form" of the equation of a line is:
→ " y − y₁ = m(x −x₁) " .
We are given the slope, m" , is: " - 3 " ;
We are given a point on the line [on the graph that is represented by this equation]; with the coordinates: " (-2 , 1) " ;
→ which is in the format: " (x₁ , y₁) " ;
→ As such: " x₁ = -2 " ; " y₁ = 1 " ;
_____________________________________________________
As aforementioned, the equation of a line in "point-slope form" ; is:
_________________________________________________________
→ " y − y₁ = m(x − x₁) " ;
in which:
→ "(x₁ , y₁) " represents the coordinates of a given point on the [line of the graph represented by the equation] ; AND:
→ " m " = the slope of the line [represented by the equation] " ;
We proceed by substituting our known values for "m" ; "y₁" ; and "x₁" :
→ " y − 1 = - 3(x − (-2) ) " ;
_______________________________________________________
→ Rewrite as:
_______________________________________________________
→ " y − 1 = - 3(x + 2) " ;
→ which is our answer; since it is written in "point-slope form" .
_______________________________________________________
