Question

Nth term of the sequence 8,48,288

Answer 1

Answer:

       $\bold{a_n=8\cdot\big6^{n-1}}$

Step-by-step explanation:

$a_1=8\\a_2=48\\a_3=288\\\\288:48=6\\48:8=6\\\\ \dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}= 6$

Therefore it's geometric sequence with common ratio of 6

$a_n=a_1\cdot r^{n-1}\\\\a_1=8\\r=6\\\\a_n=8\cdot6^{n-1}$