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3 years ago

Please help i have 2 questions thank you

Mathematics

1 answer:

katrin [286]3 years ago

8 0

1. second option
2. first option

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Find the numerator of the equivalent fraction with the denominator 12x - 2/3

Arada [10]

The numerator should be 8x

8 0

3 years ago

Measure (7x+1) (2x+1)

Gemiola [76]

Smaller angle = 41°

Larger angle = 139°

Step-by-step explanation:

(7x - 1) + (2x + 1) = 180

7x + 2x - 1 + 1 = 180

9x = 180

x = 20

The measure of the smaller angle is

2x + 1

= 2(20) + 1

= 40 + 1

= 41°

The measure of the larger angle is

7x - 1

= 7(20) - 1

= 140 - 1

= 139°

4 0

3 years ago

Read 2 more answers

The number of cubic units in the volume of a sphere is equal to the number of square units in the surface area of the sphere. Wh

viktelen [127]

Answer:

Radius of sphere is 3 units.

Step-by-step explanation:

Volume of sphere is given by $4/3 \pi r^3$

surface area of sphere is given by $4 \pi r^2$

where r is the radius of the sphere.

Given that

The number of cubic units in the volume of a sphere is equal to the number of square units in the surface area of the sphere.

we equate formula of Volume of sphere and surface area of sphere

assuming r as the radius.

thus,

$4/3 \pi r^3 = 4 \pi r^2\\\\4/3 \pi r^3/ 4 \pi r^2 = 1\\=>r/3 = 1\\=> r = 3$

Thus, radius of sphere is 3 units.

5 0

3 years ago

PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi

Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

$Hypotenuse^2=Base^2+Perpendicular^2$

⇒ $5^2=3^2+4^2$

Let a, b, c forms a Pythagorean triplet

$a^2+b^2=c^2$

Multiplied by 4 on both sides

⇒ $4a^2+4b^2=4c^2$

⇒ ${2a}^2+{2b}^2={2c}^2$

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

4 0

3 years ago

Read 2 more answers

Factor the following problems -13=-4a-2b+c 3=4a+2b+c 5=16a+4b+c Please Help!

Pie

1) -13 = -4a - 2b + c
-13 = -2(2a + b) + c

2) 3 = 4a + 2b +c
3 = 2(2a + b) + c

3) 5 = 16a + 4b + c
5 = 4(4a + b) + c

[ Final Answers are in bold ]

Hope this helps!

8 0

3 years ago