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levacccp [35]
3 years ago
8

Please help i have 2 questions thank you

Mathematics
1 answer:
katrin [286]3 years ago
8 0
1. second option
2. first option
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Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
3 years ago
I need help with this math problem it should be easy but im not good in math sooo...
ozzi
Angles in a triangle adds up to 180
All you do it 59+69 which is 128
Then you do 180-128 the answer is 52
3 0
2 years ago
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What is the coefficient of the x6y3 term in the expansion of (x + 2y)9?
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Please look to the attachment   

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3 years ago
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What is the measure of angle z in this figure?
ASHA 777 [7]

Answer:

z = 137°

Step-by-step explanation:

z^{o} =(180-43)^{o} =137^{o}

Hope this helps

7 0
2 years ago
Please help me with this question
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The equation is 240/4.75

so the answer should be 50
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2 years ago
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