2 years ago

Write out the first five odd numbers, starting at 1

Mathematics

1 answer:

atroni [7]2 years ago

4 0

Answer:

1, 3, 5, 7, 9

Step-by-step explanation:

hope this helps!

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PLEASE HELP!!!!!!!!!!!!!!!!!!!!

rodikova [14]

It's c for the answer

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3 years ago

Answer answer questions please

zloy xaker [14]

Answer: 2 1/4

Step-by-step explanation: theirs 2 whole so with that theirs another circle cut in 4th's and 1 is shaded so 1/4.

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2 years ago

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Lin and andre biked home from sxhool at a steady pace. Lin biked 1.5km and it took her 5 minutes. Andre biked 2km and it took hi

ch4aika [34]

Lin : 1.5 km in 5 minutes = 1.5 / 5 = 0.3 km per minute
Andre : 2 km in 8 minutes = 2 / 8 = 0.25 km per minute

so Lin is biking faster

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3 years ago

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What’s the point of the tangency

lbvjy [14]

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So M is correct.

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4 years ago

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If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2

ipn [44]

Answer:

$g(x)=x+1$

The problem:

Find $g(x)$ if $h(x)=(f \circ g)(x)$ ,

$h(x)=\sqrt[3]{x+3}$ , and

$f(x)=\sqrt[3]{x+2}$ .

Step-by-step explanation:

$h(x)=(f \circ g)(x)$

$h(x)=f(g(x))$

Replace $x$ in $f(x)=\sqrt[3]{x+2}$ with $g(x)$ since we are asked to find $f(g(x))$ :

$\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}$

$\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}$

This implies that $x+1=g(x)$

Let's check:

$(f \circ g)(x)$

$f(g(x))$

$f(x+1)$

$\sqrt[3]{(x+1)+2}$

$\sqrt[3]{x+1+2}$

$\sqrt[3]{x+3}$ which is the required result for $h(x)$ .

6 0

3 years ago