Answer:
Very certain it is C
Step-by-step explanation:
There are no points on the graph line itself so I cannot really confirm this but i am 70% sure
Step-by-step explanation:

Solving this equation using the quadratic formula, we get two real solutions :
1.1926 or -4.1926
Now we know the values of v , we can calculate x since x is ∛ v

![x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B3%5D%7B1.1926%7D%20%20%3D%201.0605%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B%20-%204.1926%7D%20%20%3D%20%20-%201.6125)
For this case, the first thing you should do is take into account the irrational number definition.
An irrational number is one that can not be written as the quotient between two whole numbers.
Their number of decimals is unlimited and they are not periodic.
An irrational number within the specified domain is:
π/2 = 1.570796327
Answer:
an example of an irrational number that is less than 2 and greater than 1.5 is:
π/2 = 1.570796327
Answer:
About 2.57
Step-by-step explanation:

Hope this helps!
Answer: 0.73
Step-by-step explanation: