Answer:
<h2>
8 units²</h2>
Step-by-step explanation:
Let side of the square = a
The , Area of square = a²
Now, Midpoint of Diagonal DB is E
And DE = 2 units
So, DB = 2 DE = 2 × 2 = 4 units
Now, using Pythagoras theorem in ∆ BCD
DB² = DC² + BC²
plug the values
Collect like terms
Evaluate the power
Swipe the side of the equation
Divide both sides of the equation by 2
Calculate
Therefore, The area of the square is 8 sq.units.
Hope this helps..
Best regards!!
13.45 will be the answer
since we are finding the hypotenuse, the formula is a^2 + b^2 = c^2
this will then be 10^2 + 9^2 = c^2
181=c^2
c=13.45 :)
9*13=117
12*16=192
We increased three meters to both the length and width of the garden.
Set it up like a regular equation. I used:
As you can see, however, I inserted the "less than" symbol rather than the equal sign because values greater than a certain value can also equal "x". Solve it like a normal equation and you will arrive at:
<u>
</u>
This means that, as long as x is greater than 45, "6x" will be greater than "3x+135". Thus, if you bring 46 students, the Science Center will cost less.
