Drop the percent sign so that you only have 96 then divide by 100 to get the decimal (or move the decimal place to the left two).
96% --- drop the percent
96 ----- move the decimal place over to or divide by 100
96/100
96.0
.96
Answer:
D. (6,-1)
Step-by-step explanation:
Translating is just sliding slide the point B down 4 units from where it is and then move over 6 units to the right.
By evaluating the function, we conclude that f(10) = -7
<h3>
How to evaluate the function f(x)?</h3>
Here we know that:
g(x) = 2x - 8
And f(x) = 5 - g(x).
Then we can write:
f(x) = 5 - (2x - 8) = 5 - 2x + 8 = -2x + 13
Now we want ot evaluate it in x = 10, this means replace the variable by the number 10.
f(10) = -2*10 + 13 = -20 + 13 = -7
Then, we conclude that f(10) = 7
If you want to learn more about evaluating:
brainly.com/question/1719822
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Answer: a.) $50188 to $57812
Step-by-step explanation: <u>Confidence</u> <u>Interval</u> (CI) is an interval of values in which we are confident the true mean is in.
The interval is calculated as
x ± ![z\frac{s}{\sqrt{n} }](https://tex.z-dn.net/?f=z%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%20%7D)
a. For a 95% CI, z-value is 1.96.
Solving:
54,000 ± ![1.96.\frac{6000}{\sqrt{12} }](https://tex.z-dn.net/?f=1.96.%5Cfrac%7B6000%7D%7B%5Csqrt%7B12%7D%20%7D)
54,000 ± ![1.96\frac{6000}{3.464}](https://tex.z-dn.net/?f=1.96%5Cfrac%7B6000%7D%7B3.464%7D)
54,000 ± 1.96*1732.102
54,000 ± 3395
This means the interval is
50605 < μ < 57395
<u>With a 95% confidence interval, the mean starting salary of college graduates is between 50605 and 57395 or </u><u>from 50188 to 57812$.</u>
<u />
b. The mean starting salary for college students in 2017 is $50,516, which is in the confidence interval. Therefore, since we 95% sure the real mean is between 50188 and 57812, there was no significant change since 2017.
Answer:
7. 25% of the merchants who purchase goods from Asia also purchase from Europe.
Step-by-step explanation:
I am going to say that:
A is the percentage of merchants who purchase goods from Asia.
B is the percentage of merchants who purchase goods from Europe.
We have that:
![A = a + (A \cap B)](https://tex.z-dn.net/?f=A%20%3D%20a%20%2B%20%28A%20%5Ccap%20B%29)
In which a is the probability that a merchant purchases goods from Asia but not from Europe and
is the probability that a merchant purchases goods from both Asia and Europe.
By the same logic, we have that:
![B = b + (A \cap B)](https://tex.z-dn.net/?f=B%20%3D%20b%20%2B%20%28A%20%5Ccap%20B%29)
Which of following statement is individually sufficient to calculate what percent of the merchants in the group purchase goods from Europe but not form Asia?
We already have B.
Knowing
, that is, the percentage of those who purchase from both Asia and Europe, we can find b.
So the correct answer is:
7. 25% of the merchants who purchase goods from Asia also purchase from Europe.