Point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)
slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7
a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)
2nd one
Answer:
X Y
-2 8
-1 7
0 6
1 5
2 4
3 3
Step-by-step explanation:
We have the equation: x+y=6
We want to get this in the form: y=mx+b (or in this case y=x+b)
To do this we need y to be positive and by itself
So we subtract y from both sides and divide by -1 (we divide by -1 because otherwise y would be negative and that does not fit our template of y=x+b)
Doing this we have
-x+6=y
From here we just plug in numbers -2 to 3 which I will assume you know how to do
X Y
-2 8
-1 7
0 6
1 5
2 4
3 3
Answer: To be able to create two intersecting arcs above and below the line segment
Step-by-step explanation:
That is one of the steps to bisecting a line segment lol
Only
<span>c) (-10,0)
because that is the only point in the shaded region.
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