Solve the following equation for x.

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

simplify both sides of the equation then isolate the variables. hope this helps

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Find the perimeter of a rectangle with a length of 6x+3 and a width of -2x-5.

blsea [12.9K]

The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4

At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5

-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5

This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!

8 0

3 years ago

Read 2 more answers

Can someone please explain how to do these?

Pani-rosa [81]

Answer:

First question answer: The limit is 69

Second question answer: The limit is 5

Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below:

$\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}$

Now putting 1 in $x$ gives us the limit:

$\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5$

So the answer is 5

3 0

3 years ago

Solve this equation 5x+2=3x-20-1x

Rainbow [258]

$5x+2=3x-20-1x\\5x+2=2x-20\ \ \ \ |subtract\ 2\ from\ both\ sides\\5x=2x-22\ \ \ \ |subtract\ 2x\ from\ both\ sides\\3x=-22\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=-\frac{22}{3}}\Rightarrow\boxed{x=-7\frac{1}{3}}$