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dusya [7]
3 years ago
10

Write the factored form of each trinomial. x^2 + 11x +28

Mathematics
2 answers:
Marina CMI [18]3 years ago
8 0

Answer:=

=(x^2+4x)+(7x+28)

=x(x+4)+7(x+4)

=(x+4)(x+7)

Step-by-step explanation:

yarga [219]3 years ago
5 0

Answer:

(x+4) (x+7)

Step-by-step explanation:

Factor x^2 + 11x + 28 using the AC method.

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Answer:

(x-1)(2x^2+x+2)

Step-by-step explanation:

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<u>Factor Theorem</u>

If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).

Substitute x = 1 into the function:

\implies f(1)=2(1)^3-1^2+1-2=0

Therefore, (x - 1) is a factor.

As the polynomial is cubic:

\implies  f(x)=(x-1)(ax^2+bx+c)

Expanding the brackets:

\implies  f(x)=ax^3+bx^2+cx-ax^2-bx-c

\implies  f(x)=ax^3+(b-a)x^2+(c-b)x-c

Comparing coefficients with the original polynomial:

\implies ax^3=2x^3 \implies a=2

\implies (b-a)x^2=-x^2 \implies b-2=-1 \implies b=1

\implies -c=-2 \implies c=2

Therefore:

\implies  f(x)=(x-1)(2x^2+x+2)

Cannot be factored any further.

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2 years ago
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