The answer is b for your question
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Answer:
Actually, the equation is
power (in Watts) = I² * r
I - current in amps and r - resistance in watts
Solving this for the current (I)
I = square root (power / resistance)
I = square root (15 / 100)
I = square root (.15)
I = 0.3872983346 amps
answer is B
Step-by-step explanation:
Please help<br>
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Novosadov [1.4K]
Since GH = PQ + RS, you would construct GH by making the line segments of PQ and RS combine to become the same length as the line segment of GH. The lengths of PQ and RS must add up to equal GH as well.
It will take the cheetah 4 seconds to run 80 yards.
Step-by-step explanation:
Given,
Distance covered by Cheetah in 5/2 seconds = 50 yards
Ratio of distance to time = ![50:\frac{5}{2}](https://tex.z-dn.net/?f=50%3A%5Cfrac%7B5%7D%7B2%7D)
Let,
x be the time required to cover 80 yards.
Ratio of distance to time = 80 : x
Using proportion;
Ratio of distance to time :: Ratio of distance to time
![50:\frac{5}{2}::80:x](https://tex.z-dn.net/?f=50%3A%5Cfrac%7B5%7D%7B2%7D%3A%3A80%3Ax)
Product of extreme = Product of mean
![50*x=\frac{5}{2}*80\\50x=\frac{400}{2}\\50x=200](https://tex.z-dn.net/?f=50%2Ax%3D%5Cfrac%7B5%7D%7B2%7D%2A80%5C%5C50x%3D%5Cfrac%7B400%7D%7B2%7D%5C%5C50x%3D200)
Dividing both sides by 50
![\frac{50x}{50}=\frac{200}{50}\\x=4](https://tex.z-dn.net/?f=%5Cfrac%7B50x%7D%7B50%7D%3D%5Cfrac%7B200%7D%7B50%7D%5C%5Cx%3D4)
It will take the cheetah 4 seconds to run 80 yards.
Keywords: ratio, division
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