a. Let
be a random variable representing the weight of a ball bearing selected at random. We're told that
, so

where
. This probability is approximately

b. Let
be a random variable representing the weight of the
-th ball that is selected, and let
be the mean of these 4 weights,

The sum of normally distributed random variables is a random variable that also follows a normal distribution,

so that

Then

c. Same as (b).
Step-by-step explanation:
helpful for you..........
Answer:
6
Step-by-step explanation:
w/w+6 = 1/2
2w = w+6
w=6
Answer:
4 x 5
Step-by-step explanation:
= [7+7 <span>÷ 7] + 4.12
= [7+1] + 4.12
= 8 + 4.12
= 12.12
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