Proper subset of a set is a subset of that is not equal to. all elements of are in but contains at least one element that is not it
example : if A = { 1,3,5} then B = {1,5} is a proper subset ofz
They can afford 9. You work it out by dividing 50.40 / 5.60
Answer:
Step-by-step explanation:
We have to find the system in which we can use the x and y from the given system of equations and make it hold true
From the given equations:
multiply top equation by -2 and add them
so, x = 6, y = 5
A: x-y = 2
6 - 5 = 1, so its not a
B: -2x + 2y = -2
-2(6) + 2(5) = -12 + 10 = -2
B works
just looking at C and D I can tell it doesnt work
So the answer is B
For it to be a linear equation, the same difference in x must produce the same difference in y always.
Choice A.
difference in x: 2 - 1 = 1
difference in y: -6 - (-2) = -4
difference in x: 3 - 2 = 1
difference in y: -2 - (-6) = 4
A difference of 1 in x gave a difference of -4 in y and another difference of 1 in x gave a difference of 4 in y.
This is not linear.
Choice B.
difference in x: 2 - 1 = 1
difference in y: -5 - (-2) = -3
difference in x: 3 - 2 = 1
difference in y: -9 - (-5) = -4
A difference of 1 in x gave a difference of -3 in y and another difference of 1 in x gave a difference of -4 in y.
This is not linear.
Choice C.
difference in x: 2 - 1 = 1
difference in y: -10 - (-2) = -8
difference in x: 3 - 2 = 1
difference in y: -18 - (-10) = -8
Do the other differences. All differences in y are -8 corresponding to a difference in x of -1.
This is linear.
Choice D.
The differences in y vary. It is not linear.
Answer: Choice C is linear.
