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3 years ago

How do you solve for h? Having trouble with #45

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

3 0

$S=2\pi r h+2\pi r^2\\
2\pi rh=S-2\pi r^2\\
h=\dfrac{S-2\pi r^2}{2\pi r}\\
h=\dfrac{S}{2\pi r}-1$

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Answer:

Step-by-step explanation:

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3 years ago

Determine if the two figures are congruent and explain your answer using transformations.

IRISSAK [1]

Answer:

Comparing each pair of lines,

AB and EF,

BC and FG,

CD and GH,

DA and HE.

For, AB and EF,

If we take a look at both the lines they are the mirror image of each other, the distance between point A and B is 1 unit upwards, and 2 unit sidewise, similarly between point E and F the distance is 1 unit upwards, and 2 unit sidewise. therefore, the length of both the lines is the same.

Also, we can use the formula, for the distance between two points on a coordinate plane,

As we can see in the image,

A = (-1, 1),

B = (-3, 2),

C = (-4, 4),

D = (-2, 6),

E = (2, 0),

F = (4, 1),

G = (5, 3),

H = (3, 5),

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AB = EF = √5,

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CD = GH = √8,

DA = HE = √26,

Therefore, the length of all the sides of the polygon are the same,

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Step-by-step explanation:

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2 years ago

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3 years ago

What number greater than 25 that have more factors then 25

Sindrei [870]

If i did the math correctly one number is 50
19 has two factors: 1, 19
21 has four factors: 1, 3, 7, 21
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Factors of 50- 1, 2, 5, 10, 25, 50
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3 years ago

The sum of two integers is 26. the sum of the squares of the two integers is 340. what is the product of the two numbers?

Phoenix [80]

Lets say that the two unknown integers are $n$ and $m$ .

We know the following things about $n$ and $m$ :

$n+m=26$
$n^2+m^2=340$

And, we want to find $nm$ .

To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

$(n+m)^2=n^2+2nm+m^2$

So, given what we know about the unknown integers, the previous can be written as:

$(26)^2=340+2nm$

We can easily solve for $nm$ :

$nm= \frac{(26)^2-340}{2}= \frac{676-340}{2}= \frac{336}{2}=168$

The answer is 168.

Another approach to solve the problem is, from the two starting equations, compute the values of $n$ and $m$ , which are 12 and 14, and directly compute their product; however, the approach described is more elegant.

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