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PilotLPTM [1.2K]
3 years ago
8

HELP: Find the equation of the linear function represented by the table below in slope-intercept form. (image included)

Mathematics
1 answer:
g100num [7]3 years ago
4 0

Given:

The table of value of a linear function.

To find:

The linear function in slope intercept form.

Solution:

Slope intercept form:

y=mx+b

Where, m is slope and b is y-intercept.

Consider any two points from the given table.

It is clear that the linear function passes through the points (1,0) and (2,5). So, the equation of the linear function is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-0=\dfrac{5-0}{2-1}(x-1)

y=\dfrac{5}{1}(x-1)

y=5(x-1)

Using distributive property, we get

y=5(x)+5(-1)

y=5x-5

Therefore, the slope intercept form of the given linear function is y=5x-5.

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Jordan is running 5 miles for cross-country practice (track). She ran the first 2 miles in 12.5 minutes. How long will it take h
pochemuha

Answer:

31.25 minutes

Step-by-step explanation:

12.5 minutes divided by 2 (miles) = 1 mile per 6.25 minutes

6.25 x 5 = 31.25

6 0
3 years ago
Complete the table of values for y=6-2x<br><br> Also please work out 6-2x=3
Whitepunk [10]

Answer:

Step-by-step explanation:

x=0     y=6-2*0=6

x=1      y=6-2*1=4

x=2      y=6-2*2=2

x=3      y=6-2*3=0

6-2x=3

-6       -6

-2x=-3

2x=3

:2    :2

x=3/2

x=1.5

3 0
4 years ago
Please help me find the answer
mixas84 [53]
136 would be the answer
5 0
3 years ago
There are 7 girls on a bus. each girl has 7 backpacks. each backpack has 7 big cats. each big cat has 7 little cats. how many le
Vera_Pavlovna [14]
7 girls on a bus, each has two legs. 7 * 2 = 14. 

Each girl has 7 backpacks. So 7 * 7 = 49. 

49 * 7 = 343 cats in total 

343 * 4 = 1,372 cat legs. 

343 * 7 = 2401 small cats 

2401 * 4 = 9,604 cat legs 

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6 0
3 years ago
Read 2 more answers
Use the given function and the given interval to complete parts a and b. f (x )f(x)equals=negative 2 x cubed plus 21 x squared m
Leya [2.2K]

Answer:

(A)The absolute maximum of f(x) is at x=5

Step-by-step explanation:

F(x)=−2x³+21x²−60x on [1,6]

Find the first derivative.

f'(x)=-6x²+42x-60

Set the first derivative equal to zero.

-6x²+42x-60=0

Solve to find the critical points.

x=2,5

Next, we use the endpoints and all critical points on the interval to test for any absolute extrema over the given interval.

x=1,2,5,6

This is done by evaluating the function at x=1,2,5,6.

F(1)=−2(1)³+21(1)²−60(1)=-41

F(2)=−2(2)³+21(2)²−60(2)=-52

F(5)=−2(5)³+21(5)²−60(5)=-25

F(6)=−2(6)³+21(6)²−60(6)=-36

The maximum will occur at the highest f(x) value and the minimum will occur at the lowest f(x) value.

Absolute Maximum: (5,-25)

Absolute Minimum: (2,-52)

The graph is attached.

The absolute minimum and maximum of f(x) are (2,-52) and (5,-25) respectively.

3 0
3 years ago
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