Answer:
Domain of y=
: is x>=1
Interval notation: [1,∞)
Step-by-step explanation:
We have y=![\sqrt[4]{x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx-1%7D)
1) The domain of a function is the set of x values for which the function is real and defined.
2) So, x-1 should be positive means x-1>=0, because fourth root of any negative value would be a complex number and not a real number.
3) Now we solve the inequality x-1>=0
4) Adding 1 to both sides of the inequality we get,
x-1+1 > = 0+1
5) Cancel out -1 and +1 from the left side
6) We get x>=1
It concludes that for the domain of the given function, the x value must be greater than or equal to 1
Plug it in.
y = -1, y1 = 1
x = 3, x1 = 1
-1 - 1 = m( 3 - 1)
-2 = 2m
m = -1
The slope is -1
y = -x +b
-1 = -3 +b
b = 2
The equation is y = -x + 2
Hope this helps.
The rule P(x, y)→P'<span>(x+10, y−6),
shifts point P 10 units right and 6 units down.
Point G(-7, 4) under the rule </span>G(x, y)→G'(x+10, y−6) is translated as follows:
<span>
P (-7+4)</span>→P' (-7+10, 4−6)= P'(3, -2)
<span>
Answer: P'( 3, -2)
</span>
Hello!
When you divide two exponents with the same base you can subtract the exponents
2^5 / 2^3 = 2^2
2^2 = 4
The answer is C) 4
Hope this helps!