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3 years ago

Hey yall like dat sweet algeba? then 5ab - 2c where a = 2 b = 3 and c is 0. gud luck daddio

Mathematics

1 answer:

nordsb [41]3 years ago

7 0

Answer:

Step-by-step explanation:

5ab-2c

5(2)(3)-2(0)

5(6)-2(0)

30-0

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Write the expression using rational exponents. Then simplify and convert back to radical notation.

ioda

Answer:

The radical notation is $3x\sqrt[3]{y^2z}$

Step-by-step explanation:

Given

$\sqrt[3]{27 x^{3} y^{2} z}$

Step 1 of 1

Write the expression using rational exponents.

$\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}$

$=a^{\frac{m}{n}}:\left({27 x^{3} y^{2} z})^{\frac{1}{3}}$

$(a \cdot b)^{r}=a^{r} \cdot b^{r}:(27)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

$=$(3^3)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$$

$=\left(3\right)\left(x}\right)} \cdot\left(y}\right)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

Simplify $3 x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3 x \sqrt[3]{y^{2} z}$

Learn more about radical notation, refer :

brainly.com/question/15678734

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2 years ago

What is the domain of the function?

Ket [755]

Answer:

(-∞,∞)

Step-by-step explanation:

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2 years ago

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Two sides of a triangle are 4 meters and 12 meters long . Which of the following is not a possible length of the third side?

natulia [17]

Answer:

it is D

Step-by-step explanation:

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2 years ago

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Natalie Albert deposited checks totaling $1,735,97 into her savings account. She withdrew $100.00 while

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Anything withdrawn you subtract. Then, you know the total and you know what you had. Subtract total from what you had and you will see the change.

1735.97-100=1635.97

1668.71-1635.97=32.74

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2 years ago

Can you help me plzs

Jlenok [28]

Answer:

164

Step-by-step explanation:

2x+7+5x+12=180

7x+19=180

7x+180-19

7x=171

---- ----

7 7

x=164

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3 years ago

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