Answer:
13) 10b^2a^4
14) -5y^3+35y^2-10y
Answer:
87-13 = 74
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
I am pretty sure but get another answer just to be sure.
Option C
The distance of a spin of one full rotation is 31.4 feet
<em><u>Solution:</u></em>
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
<em><u>The circumference of circle is given as:</u></em>

Where "r" is the radius

Thus the distance of a spin of one full rotation is 31.4 feet