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3 years ago

1. What is the opposite of -17

Mathematics

2 answers:

insens350 [35]3 years ago

7 0

17 is the opposite my friend.

djyliett [7]3 years ago

5 0

Answer:

Step-by-step explanation:

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Lois and Clark own a company that sells wagons.The amount they pay each of their sales employees (in dollars) is given by the ex

Karolina [17]

12h + 30w represents the amount paid to each employee.....where h is the number of hrs and w is the number of wagons sold.

working 6 hrs and selling 3 wagons.....so h = 6 and w = 3

12h + 30w = total pay
12(6) + 30(3) =
72 + 90 =
162 = total pay <===

8 0

3 years ago

7x+2y=-19 and -x+2y=21

Fittoniya [83]

Subtract the 2 equations

7x+2y=-19
- -x+2y = 21
--------------------------
8x +0y=-2

x= -1/4

7 0

3 years ago

Which of the following prefixes is the best for measuring small quantities like the thickness of a dime A.milli B.kilo C.deci D.

never [62]

Milli is the best to measure the thickness of a dime. A is your answer.

6 0

3 years ago

We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

6 0

3 years ago

he marked price of a ceiling fan is ₹720. During off season, it is sold for ₹684. Find the discount percent.

saw5 [17]

Step-by-step explanation:

$\frac{720 - 684}{720} = 0.05 = 5\%$

5 0

2 years ago

Read 2 more answers