Ill mark brainllest not all tiles will be used

I need help fasttt with work

Vlad [161]

Answer:

-19.9 ft.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The figure shows a circle with center P and inscribed isosceles Triangle ABC. If AC has the same length as the radius of the cir

Ksenya-84 [330]

Answer:

<ABC = $30^{0}$ (The central angle of a circle is twice any inscribed angle subtended by the same arc).

Step-by-step explanation:

From the diagram, ABC is an inscribed isosceles triangle. But the radius of the circle equals the length AC.

Join P to A and C to form an equilateral triangle. An equilateral triangle has equal sides and angles. So, the value of each interior angle of the equilateral triangle is;

Sum of angle in a triangle = $180^{0}$

So that each interior angle = $\frac{180^{0} }{3}$

= $60^{0}$

The value of each interior angle of the triangle is $60^{0}$ . Thus, <APC = $60^{0}$ .

⇒ <ABC = $30^{0}$ (The central angle of a circle is twice any inscribed angle subtended by the same arc.)

7 0

3 years ago

The house down the street has termites in the porch. The exterminator estimated that there are

Rzqust [24]

Answer: 5832.5602

Step-by-step explanation:

6 0

3 years ago

Yoshiko collected some bottle sto be recycled. Twelve were brown. There were 50 more clear bottles than brown ones. There were 3

snow_lady [41]

So we know there are 12 brown ones
brown=12
50 more than 12 is the number of clear bottles so 50+12=62

brown=12
clear=62

30 numbers down from 62 is the number of green ones so 62-30=32

brown=12
clear=62
green=32

12+62+32=106

so Yoshiko collected 106 bottles

3 0

3 years ago

According to the U.S. Census Bureau, 11% of children in the United States lived with at least one grandparent in 2009 (USA TODAY

wel

Answer:

The pvalue of the test is 0.0001 < 0.02, which means that we reject the null hypothesis and accept the alternate hypohteis that the proportion of all children in the United States who currently live with at least one grandparent is higher than 11%.

Step-by-step explanation:

Proportion of all children in the United States who currently live with at least one grandparent is higher than 11%

This means that the null hypothesis is:

$H_0: p = 0.11$

And the alternate hypothesis is:

$H_a: p > 0.11$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.11 is tested at the null hypothesis:

This means that $\mu = 0.11, \sigma = \sqrt{0.11*0.89}$

Suppose that in a recent sample of 1550 children, 214 were found to be living with at least one grandparent.

This means that:

$n = 1550, X = \frac{214}{1550} = 0.1381$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.1381 - 0.11}{\frac{\sqrt{0.11*0.89}}{\sqrt{1550}}}$

$z = 3.54$

Pvalue of the test and decision:

This is the probability of finding a sample proportion above 0.1381, which is 1 subtracted by the pvalue of Z = 3.54.

$z = 3.54$ has a pvalue of 0.9999

1 - 0.9999 = 0.0001

The pvalue of the test is 0.0001 < 0.02, which means that we reject the null hypothesis and accept the alternate hypohteis that the proportion of all children in the United States who currently live with at least one grandparent is higher than 11%.

8 0

2 years ago