Large red ones= 16/78
33-16=17 small gumdrops
22 gumdrops are small
small red ones=17/22
Probability of large and small red ones:
prob. of large red ones: 16/78+22/22= 38/100=38%
prob. of small red ones: 17/22+78/78= 95/100=95%
Answer:
Following are the solution to the given question:
Step-by-step explanation:
Confidence Interval for both the percentage of all x-ray machines
p = the machinery's share is not working:
Lower Confidence interval = p - error margin 
Upper Confidence Interval = p + error margin
So, Confidence Interval 
Answer:
9.09
Step-by-step explanation:
x=speed of boat
y=speed of water current
Downstream relative speed = x+y
Upstream relative speed = x-y
Distance remains the same for both upstream and downstream.
a) Distance travelled downstream = speed x time = 3(x+y)
Distance travelled upstream = speed x time = 3.6(x-y)
b) Since both distances are equal, we can write
3(x+y)= 3.6(x-y)
3x+3y = 3.6x-3.6y
6.6y = 0,6x
x=11y: y=x/11
c) Water current has speed as 1/11 times of that of boat
In percent this equals 100/11 = 9.09%
Answer:
1. m=- -1 2. -1+1
Step-by-step explanation:
Ok for the first one you need to label 3 x1 0 y1 6 x2
and -3 y2
Next you need to do y2-y1 over x2-x1 so fill that in and your equasion is (-3-0)
------------ = -3
( 6-3) ----
3
That reduces to -1 because -3 divided by 3 is -1
As for number 2 we need to find b to do this pick any of the y's from before we can go with 0 so the 0 is y in the equasion and we already learned slope is -1 so your equasion should be 0=--1+b ok to solve this you need to add -1 to both sides since its a negitive so you add 1 to 0 which is 1 and when you add 1 to -1 it cancells it out so you have 1=b so b is 1 for the equsion you just fill it in so it is y=- -1+1
I hope I helped
You know how Soh Cah Toa applies to right triangles; you can assign the adjacent side = 4 and hypotenuse = 7
CosФ = (adjacent) / (hypotenuse)
Then with the Pythagorean theorem
4² + b² = 7²
16 + b² = 49
b² = 49 - 16
b² = 33
b = √(33)
So "b" is the opposite side.
SinФ = (opposite) / (hypotenuse) = √(33)/7
TanФ = (opposite) / (adjacent) = √(33)/4
