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klemol [59]
4 years ago
13

What is the length of the radius?

Mathematics
2 answers:
alexira [117]4 years ago
8 0
I believe it should be 4.8
deff fn [24]4 years ago
4 0
The answer is 8.4.

I would use the Pythagorean Theorem to solve this:
  l² + l² = h²
  r² + (5)² = (9.8)²
  r² + 25 = 96.04
  r² = 96.04 - 25
  √r² = √71.04
  r = 8.428523...
  r = 8.4

Hope that helps.
You might be interested in
What inverse operation would you perform on both sides to solve this equation?
Lesechka [4]

Answer:

c=-24

Step-by-step explanation:

You should perform the inverse of addition and multiplication

The inverse of addition is subtraction so we subtract 4 on both sides:

4-4-c=26-4

Which will be

-c=24

Divide by -1 since the inverse of multiplication is division

-c/-1=24/-1

So the answer will be:

c=-24

5 0
3 years ago
Read 2 more answers
) Thirty percent of the students in a management class are graduate students. A random sample of 3 students is selected. a) Usin
adell [148]

Given Information:  

Probability of success = 30%

Sample size = n = 3

Variable of interest = x = 2  

Required Information:  

Probability of exactly 2 graduates = ?

Answer:

Probability of exactly 2 graduates = P(2; 3, 0.30) = 0.189

Step-by-step explanation:

The given problem can be modeled as a binomial experiment since a random selected student can either b graduate or not therefore, there are only 2 outcomes. Each trial is independent and the probability of success is not changing from trial to trial. The number of trials in also fixed.

We know that a binomial distribution is given by

P(x; n, p) = nCx pˣ (1 - p)ⁿ⁻ˣ

Where p is the probability of success and 1 - p is the probability of failure, n is number of independent trials and x is the variable of interest.

For the given problem, we know that x = 2, n = 3 and p = 0.30

P(2; 3, 0.30) = 3C2*0.30²*(1 - 0.30)³⁻²

P(2; 3, 0.30) = 3*0.30²*(0.70)¹

P(2; 3, 0.30) = 0.189

3 0
4 years ago
I need the answer for this problem
kiruha [24]

Answer:

1.8x10^-4

Step-by-step explanation:

I did it by the calculator

8 0
3 years ago
1. Let x[n] be a signal with x[n] = 0 for n<-1 and n > 3. For each signal given below, determine the values of n for which
valentina_108 [34]

Answer:

a) n<1 and n>5

b)  0 < n < -4

c)  n > 2 and n < -2

Step-by-step explanation:

The signal is given by x[n] = 0 for n < -1 and n > 3

The problem asks us to determine the values of n for which it's guaranteed to be zero.

a) x[n-2]

We know that n -2 must be less than -1 or greater than 3.

Therefore we're going to write down our inequalities and solve for n

n-2

Therefore for n<1 and n>5 x [n-2] will be zero

b) x [n+ 3]

Similarly, n + 3 must be less than -1 or greater than 3

n+30

Therefore for n< -4 and n>0, in other words, for 0 < n < -4  x[n-2] will be zero

c)x [-n + 1]

Similarly, -n+1 must be less than -1 or greater than 3

-n+13-1\\-n>2\\n

Therefore, for n > 2 and n < -2  x[-n+1] will be zero

4 0
4 years ago
Subtract -3x-4 from 7x^2-7x​
professor190 [17]

Answer:

−49x8−3x−4

Step-by-step explanation:

−3x−4−49x7x

=−3x+−4+−49x8

hope this helps

4 0
4 years ago
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