Answer:
<h2>bhlhgewafhjffdgnhgreesdbjit<u>bbbbhbfghjkkbiiuu</u><u>h</u><u>h</u><u>h</u></h2>
Answer:
Step-by-step explanation:
An Albert Einstein iconic math problem.
Answer:
37.5
Step-by-step explanation:
Answer:
a2 =14
a4 = 22
a11 = 50
Step-by-step explanation:
an = 10 + (n-1) *4
n is the term number
Let n =2
a2 = 10 +(2-1)*4 =10 +(1)*4 = 14
Let n =4
a4= 10 + (4-1)*4 = 10 *3*4 = 10+12 = 22
Let n = 11
a11 = 10 +(11-1)*4 = 10 *10*4 = 10+40 = 50
<span> If all numbers are greater than zero and no repeated numbers exist these are the 5 possible combinations:
1 + 2 + 8
1 + 3 + 7
1 + 4 + 6
2 + 3 + 6
2 + 4 + 5.
If one number is allowed to be zero and no repeated numbers exist these are 5 combinations:
</span><span> 0 + 11
1 + 1 + 9
2 + 2 + 7
3 + 3 + 5
4 + 4 + 3
5 + 5 + 1
</span><span>
Hope this helps
</span>
