Answer:
12^5
Step-by-step explanation:
36^5=3^5×x^5
36÷3=12
First of all, we can simplify the dividend:
![-2x+11x^2-23x+20=11x^2-25x+20](https://tex.z-dn.net/?f=-2x%2B11x%5E2-23x%2B20%3D11x%5E2-25x%2B20)
so we can rewrite our problem as 11x^2-25x+20 divided by
![x^2-3x+4](https://tex.z-dn.net/?f=x%5E2-3x%2B4)
.
Now, to find the result of the division, we are going to perform long division as you can see in the attached image.
We can conclude that the result of of dividing
![11x^2-25x+20](https://tex.z-dn.net/?f=11x%5E2-25x%2B20)
by
![x^2-3x+4](https://tex.z-dn.net/?f=x%5E2-3x%2B4)
is
![11](https://tex.z-dn.net/?f=11)
with a remainder of
![8x-24](https://tex.z-dn.net/?f=8x-24)
, or in other notation:
<em><u>Answer</u></em>
In order to use the distributive property I first get the amount of the water fell in ;
<u>One </u><u>year</u>
1.68mm
<u>A </u><u>half</u><u> </u><u>a </u><u>year</u>
½× 1.68mm
= 0.84mm
<u>One </u><u>and </u><u>a </u><u>half </u><u>years (</u><u>Using </u><u>the</u><u> </u><u>distributive</u><u> </u><u>property</u><u>)</u>
1.68mm + 0.84mm
<u>1</u><u>6</u><u>8</u><u>m</u><u>m</u> + <u>8</u><u>4</u><u>m</u><u>m</u>
100. 100
(168÷100) + (84÷100)
(168+84) ÷ 100
252 ÷ 100
<u>2</u><u>5</u><u>2</u>
100
= 2.52mm
Therefore the variation in the water level in the time period was 2.25mm
Answer:
10 for 9$
Step-by-step explanation:
because say the each ball cpsts a dollar, and the total for 3 would be 3$ for the cost of 10 would be 9 so its less but more mo ey spent